All Answers 358099 Answers

You were kidding? Ughhh. -.- 

I can help you! :)

First, You must answer :)

Do you see a blue box that says "ask question" or something??

Some stuff happened, Family stuff. Im back now :)

Yeah

Sorry, CPhill: After my 4th. comment above, I went to bed! It turns out that the answer is surprisingly simple. It is a relatively common and well-known TVM formula widely used in advanced accounting. And it is this:

FV= G {[1 + R]^N - RN - 1} / R^2=

FV= G {[ 1 + .05]^100 -(.05*100) - 1} / .05^2. Where:

G is a steadily increasing payment amount, that starts at G and increases by G for each subsequent period.

FV= 1{ 131.50125... - 5 - 1} / 0.0025

FV= {125.50125} / .0025

FV=$50,200.50.

And that is the answer in the book. Great effort on your part though, and I thank you.

707 + 707 = 700 + 700 + 7 + 7 = 1400 + 14 = 1414

find common denominator

5+(20/16)+(5/16)

add fractions, just the top part, leave denominator

5+(25/16)

make common denominator for the 5

[(5*16)/16]+(25/16)

simplify

(80/16)+(25/16)

=105/16 = 6.5625 

find common denominator

5+(20/16)+(5/16)

add fractions, just the top part, leave denominator

5+(25/16)

make common denominator for the 5

[(5*16)/16]+(25/16)

simplify

(80/16)+(25/16)

=105/16 = 6.5625 

The answer is 90 kph

let s find how much she spend:

3/5+1/3=14/15 

how much she left:

1-14/15=1/15

so 1/15 is 20$

20x15=300 (it is the money which she withdrew)

300x3=900

Answer:900

the average of 1 ticket will be 43/7

A-average of tickets

G-General Admission tickets

R-Reserved Seat tickets

G               A                           R

4_______43/7____________9

    15/7                 20/7

distance from G to A is:

lG-Al=l4-43/7l=15/7 

distance from R to A:

lR-Al=l9-43/7l=20/7

So the ratio     G           :             R

                      20/7                    15/7

                           20/7:15/7=4:3

                        4                          3

SO there was:

4 General admission ticket for $4: 4x4=16

3  Reserved Seat tickets for $9: 3x9=27

you messaged me the same question please next time send me the link of the question !

So simple, it's 9.

All the Best for the Finals rarinstraw!! Luckily my Finals are in March!

So can I solve questions from Guests (If I know the answer)?

First look at the following diagram:

From this we see that        \(\sin{30°}=\frac{1}{2}\\\\ \cos{30°}=\frac{\sqrt{3}}{2}\)

Can you take it from here?

Bee sting molecules

Thanks Melody!

Here is WolframAlpha's answer:

Or:

\(5^\frac{9}{2}\rightarrow\sqrt{5^8\times5}\rightarrow5^4\sqrt{5}\rightarrow 625\sqrt{5}\)

You don't say in respect to which direction the angle is measured!!

If we assume it is 61° to the horizontal then the component of force in the vertical direction is 182*sin(61°) N

If it is 61° to the vertical then the compponent of force in the vertical direction is 182*cos(61°) N

Chris, haven't you tried to put the three people together rather than NOT together ?

-----------------------

"7 position possibilities * 6 arrrangements of the three people for each position possibility* 24 arrangements of the other 4 people   = 1008 ways"

I am going to assume that is what you have tried to find. And I will look at your logic.

Yes there are 6 ways to seat the 3 that will remain together - in relation to each other.

So we will take one of these arrangements and seat these three people.

Noy you are right i believe, there are 4! = 24 arangements for the other 4

6*24=144     Yes so far I agree.

The you multiply this andwer by 7.....     Why did you do that ?
 

If this is supposed to be

[(-2/5)(log₂ (2)] / 5    -  [(3/5) log₂ (3)] / 5       we have

(-2/25) (1)  -  (3/25) [ log (3) ]  /  [ log(2)    ≈ -0.2701955

 However, if this is supposed to be

(-2/5) log₂ (2/5)  - (3/5)log₂ (3/5)    then we have

(-2/5) log₂ (0.4)  - (3/5)log₂(0.6)  ≈  0.970951

[ The use of parentheses is important in these problems.....!!!! ]

Thanks, heureka   !!!!

OK...sorry....I did my best......if heureka doesn't provide us with an answer, why don't you post the shortcut on here....????......

Thanks, CPhill