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3people out of 100

Thanks so much, you guys are awesome :)

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Chris to the rescue!!

Here you go, jc   http://www.regentsprep.org/Regents/math/geometry/GP15/CircleAngles.htm

Look at the second property......

thanks :) 

Good 4 u. Good luck. Do you know each other in real life?

??? Overdrive?

OverDrive. Just need a library Card. :)

Hey Chris.....   Help me....  How do you know that the inscribed angle  measures 1/2 of it's intercepted arc??

Thanx

~jc

Uh-oh! Two different Answers?

I would think, 3x+y=14

Get lost, Loser        Note:  Loser with a capital 'L'

The inscribed angle in the circle measures 1/2 of its intercepted arc.......so z°   = 80°

Then.....the other two arcs must comprise 360 - 80  =  280°  of arc.......therefore

(2x + 20) + (4x + 40)  = 280   simplify

6x + 60  =  280     subtract 60 from both sides

6x = 220     divide both sides by 6

x = [36 2/3]°

(C) 

I wish I could draw this out....but    basically   40 + (2x +20) + (4x + 40) = 360 degrees

solve for x        x = 43 2/3 degrees

If you look at the vertex of the angle you have one arm that has rotated 40 degrees.....rotate that arm another  2x+20 degrees   then another 4x + 40 degrees for a complete circle (360 degrees)

So  40 + (2x+20) + (4x+40) = 360

~jc

1

 99

 x 2

198

here it is!

ohh. :p

Yeah we have been for like 3 or 2 weeks

15 there are 5 1/5 in 1 therefore 15 1/5 in 3

2*(99)

198..

Have a great day!

Are yall dating?? O__O

Lol I meant him but okay love you to!!😂

That's not nice, Guest....

Grow up and stop being nasty!!!

I love youu!! :D?