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Iz gud, bter ten u, m8.

Hey, Girly!! :)

Yes, Solviet :)

That's all they gave me :/

Dat iz nono tru. Dis quest sion waz made bi illuminati!

Solveit, U men gave*, gived iz nono word U reaturd!

If there is a sertain number and someone takes 1/3 of the number then takes 1/4 of the number then someone takes 1/2 of the number. If the ending number is 6 than what was the starting number

\(\begin{array}{rcll} n\cdot \frac13 \cdot \frac14 \cdot \frac12 &=& 6 \\ n &=& 6 \cdot 3 \cdot 4 \cdot 2 \\ n&=& 144 \end{array}\)

Y(x+2)2 is that all that they gived to you ?

Would the starting number be 8?

Is it Multiple choice?

Mybeh U can gat gud to answear dis mth problam???

Ah fel dat UR stapid, U gt to get gud, m8. U cant' re-lie on dis cite, srry. ): ):) :)

It = 9.3333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333...

I'm sorry if some of those questions are stupid. :/

4x=6

4×1.5=6

x=1.5

Thank you, Sir! Have a great day!

Thank you, Sir!

y = x^3 + 3

3*8=24

7+7=14

y = x^3

8=-2

=-4

Have a great Day!

7/2 + 7

5.5

:)

You can see from the plot below that there are no real number values for which x²+xy+4y²≤ -3

Thank you!

Hi Lance and Fellowes,

You are playing a poker game called "Omaha" and are dealt 4 cards from a standard 52 card deck. How many possible combinations of hands can you be dealt that contain both at least one Ace and at least one King? Please explain your answer.

It would be easier for me to check if you had given some number answers

I am not sure if my logic is the same as yours or not.

A for ace, K for king, x for any other card

1ace

AKxx            4*4* 44C2  =  15136

AKKx            4*4C2*44  =   1056

AKKK            4* 4C3      =      16

2 aces

AAKx           4C2 * 4 * 44 = 1056

AAKK            4C2 * 4C2 =       36

3 aces

AAAK             4C3 * 4     =     16

15136+1056+16+1056+36+16 = 17316

That is what I think anyway :)

Let m = original male guppies and f = original number of female guppies.

m = f + 180     

m+65 = 5*(f-5f/8)   or  m+65 = 15f/8

Replace m in the last equation using the first equation    f + 180 + 65 = 15f/8  or f + 245 = 15f/8

 8f + 8*245 = 15f

8*245 = 7f

f =  280

Use first equation to get m then add m and f to get total.

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