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Very much so!! :]

That is adorable

40 1/3  =    121/3

7 1/3  =  22/3    

So

[121/3]  / [22/3]   =

[121/3] * [ 3/22]  =

[ 121/22] * [3/3]  =

121/22  =

11/2  =

5 1/2

What is the perimeter to a right triangle with the bottom being 3√5 and the side 2√5 (use pythagorean theorem)

[3sqrt(5)]^2 + [2sqrt(5)]^2 =H^2

[9*5] + [4*5] =H^2

45 +20 =H^2

H =+or-sqrt(65)

The perimeter of the triangle=sqrt(45) + sqrt(20) + sqrt(65)=19.24 (rounded)

Assuming that 2√5  and 3√5  are the lengths of the legs......the hypotenuse is given by:

sqrt [ (2√5)^2  + (3√5)^2 ]  =  sqrt  [ 20 + 45]  = sqrt(65)

So....the perimeter is

2√5 + 3√5 + √65   =

5√5  + √65  =   about 19.24  units

In my answer    (guest #1)   I assumed ONE of those 'x' s   was supposed to be a 'y'.....A typo I  am sure

Cos (theta)   for a given angle is    Adjacent side /  Hypotenuse      

I assume the 'bottom'  and the 'side' are not the hypotenuse

Then:   a^2 + b^2 = c^2  to find the hypotenuse

(3sqrt5)^2  +  (2sqrt5)^2  = c^2

45  +20  = c^2 = 65

c=sqrt65 =          so the perimeter is all of these sides added together

sqrt65 + 3sqrt5 + 2sqrt5  =  19.24

Use pythegorean theorm; a²⁺b²=c²

circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and r= radius

Put in standard form:

1  x^2 + y^2  = 4        4 = r^2   in this form    so r = sqrt4 = 2    the cente is  0,0

#2 (I THINK that first = is supposed to be a +)

  (x^2 +6x) + (Y^2+6y) = - 9    Complete the squares   (do you know how to do this?)

     (x^2 +6x +9) + (y^2+-6y +9) = -9 + 9 + 9

      (x+3)^2  +  (y+3)^2  = 9                               Now it is in a standard form   r^2 =9   r= sqrt9 = 3

                                                                            the center is -3,-3

es only if the divisor is smaller the the qouetshiont

Solve for x: (x-7)^2+(x-3)^2 = 225 Expand out terms of the left hand side: 2 x^2-20 x+58 = 225 Divide both sides by 2: x^2-10 x+29 = 225/2 Subtract 29 from both sides: x^2-10 x = 167/2 Add 25 to both sides: x^2-10 x+25 = 217/2 Write the left hand side as a square: (x-5)^2 = 217/2 Take the square root of both sides: x-5 = sqrt(217/2) or x-5 = -sqrt(217/2) Add 5 to both sides: x = 5+sqrt(217/2) or x-5 = -sqrt(217/2) Add 5 to both sides: Answer: | | x = 5+sqrt(217/2)     or       x = 5-sqrt(217/2)

Sqrt 225 =15

4 1/3    /  7 1/3

=  13/3    /   22/3   

=  13/3   x   3/22

= 39/66

=13/22

This circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and r=radius

r^2 = 225    so r = sqrt225 = 15

USE the calculator !

1.7

You can't figure this equation 'out'     You will need either a value for 'p' or a value for 'm' ...or another equation which relates 'p' and 'm'.    .....Sorry

Thankyou! 

022 divided by 006.6

022 / 006.6

= 22 / 6,6 = 220 / 66 = 10 / 3 = 3  1/3

!

Well, yes there can be an invisble '1' behind it.......if you are multiplying by this '1' , it won't change anything in the answer.

sqrt3   x  7   x   sqrt8

sqrt3   x   7  x   sqrt(2 x 4)

sqrt3   x   7  x  2 sqrt2

sqrt3   x 14  x  sqrt2     =   14 sqrt3 sqrt 2     or   14 sqrt6

Hallo!

2  * (2/9) - 3 + (78/6) - 3

= 4/9 + 78/6 - 6

= 8/18 + 234/18 - 108/18

= 134/18

= 7  4/9

2*2/9-3+78/6-3 = 7,444... = 7  4/9

Greeting asinus :- )

!