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Press the 2nd key, then use atan, which is the same as tan^-1

Not if every pair must be different!  There are only so many different digits you can use for the first digit of the pair and only so many for the second digit.  

The circumference of the wheel is 2*pi*14 = 28pi cm, which is the distance moved in one revolution.  Therefore it will take 890/(28pi) revolutions to move a distance of 8.9m (=890cm).

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Use v = u + a*t   where v is final velocity (0 m/s here), u is initial velocity (4 m/s), a is acceleration (-9.81 m/s²) and t is time.

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4sinx+5cosx in the form ksin(x+a)

\(\boxed{~ \begin{array}{rcll} A\cdot \sin{(x)}+ B \cdot \cos{(x)} &=& k\cdot \sin{(x+a)} \\ && k = \sqrt{A^2+B^2} \qquad a = \tan^{-1}{ \left(\frac{B}{A} \right)} \end{array} ~}\)

\(\begin{array}{rcll} A\cdot \sin{(x)}+ B \cdot \cos{(x)} &=& k\cdot \sin{(x+a)} \qquad A = 4 \qquad B = 5 \\ \qquad && k = \sqrt{4^2+5^2} \qquad a = \tan^{-1}{ \left(\frac{5}{4} \right)} \\ \qquad && k = \sqrt{16+25} \qquad a = \tan^{-1}{ (1.25 )} \\ \qquad && k = \sqrt{41} \qquad \qquad a = 51.3401917459^\circ\\\\ 4\cdot \sin{(x)}+ 5 \cdot \cos{(x)} &=& \sqrt{41}\cdot \sin{(x+51.3401917459^\circ )} \\ 4\cdot \sin{(x)}+ 5 \cdot \cos{(x)} &=& 6.40312423743\cdot \sin{(x+51.3401917459^\circ )} \\ \end{array}\)

\(\frac{6csc(20)}{13csc(0)-5}=0\)

Let's simplify  \(6csc(20)=17.5\)to 3 significant figures

\(csc(0-5)=csc(-5)\)

\(13csc(-5)=-149\)to 3 significant figures

\(\frac{17.5}{-149}\neq 0 \)Maybe if you wrote the whole decimal out it might equal zero but if we're simplifiying to 3 significant figures, it does not equal zero. 

Thanks Solveit you are always a reliable person to ask.

Guests aren't allowed on this site anymore apparently so I will answer your question anyway. 

0.971666 dollars. Just calculate like a normal division sum.

yeah

11.66/12 = 0.9716666666666667

Your sketches were amazing! G'night!