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Anytime. 

V =  L* W * H  =  12 * 5 * 9  =  540m^3

                                  10

Thanks spawn 

Verify the following identity:
2 csc(2 x)  =  cot(x)+tan(x)

Write cotangent as cosine/sine, cosecant as 1/sine and tangent as sine/cosine:
2 1/(sin(2 x))  =  ^?(cos(x))/(sin(x))+(sin(x))/(cos(x))

Put (cos(x))/(sin(x))+(sin(x))/(cos(x)) over the common denominator sin(x) cos(x): (cos(x))/(sin(x))+(sin(x))/(cos(x))  =  (cos(x)^2+sin(x)^2)/(cos(x) sin(x)):
2/(sin(2 x))  =  ^?(cos(x)^2+sin(x)^2)/(cos(x) sin(x))

Cross multiply:
2 cos(x) sin(x)  =  ^?sin(2 x) (cos(x)^2+sin(x)^2)

sin(x)^2 = 1-cos(x)^2:
2 cos(x) sin(x)  =  ^?sin(2 x) (cos(x)^2+1-cos(x)^2)

cos(x)^2+1-cos(x)^2 = 1:
2 cos(x) sin(x)  =  ^?sin(2 x)

sin(2 x) = 2 sin(x) cos(x):
2 cos(x) sin(x)  =  ^?2 cos(x) sin(x)

The left hand side and right hand side are identical:
Answer: | (identity has been verified)

Baller. Accept this answer. You cannot be forgiven at this time. Give it some more time. The pain will ease, and you can become friends again.

Bree. As I said above. The pain will ease. You will forgive her in time. If she doesn't do anything terrible in the mean time. Just keep in contact. Try not to p**s each other off to much. Let time heal the wounds. This will cause you to become friends again.

I really do love you Brianna..

2 csc 2x = cot x + tan x

2/ [sin (2x) ] = cosx/sinx  + sinx/ cosx   

Get a common denominator on the right,  use an identity on the left

2 /  [ sinxcos x + sinxcosx]  =  [  cos^2x + sin^2x] / [sinx cosx]

2/ [ 2sinxcosx] = 1/ [sinxcosx]       the 2's on the LHS "cancel".....and we're left with

1/ [sinxcosx] =  1/ [sinxcosx]

...

I don't trust you.. You love Alex don't love me.. 

People make mistakes. You guys are what? In 7th or 8th grade? Ever heard of a divorce kids? When someone cheats in a marriage, that is the first place they look. But it isn't always the answer. People can change, can forgive. Sooner you learn this, the better.

Bree im fucking sorry. I realllllly do love you.. Pleasseee..

x^2y^2 + x^2 + y^2 + 2xy = 40  →  x^2y^2 + (x + y)^2  = 40     (1)

xy + x + y = 8   →  y( x + 1)  = 8 - x   →  y  = [ 8 - x] / [ x + 1]      (2)

Put (2)  into (1)

x^2  [ 8 - x]^2 / [x + 1]^2  + [ x + [8 - x] / [ x + 1] ] ^2 = 40     simplify

x^2 [ x^2 - 16x + 64] / [ x + 1]^2  + [ x (x + 1)/(x + 1) + [ 8 - x] / [x + 1] ]^2  = 40

x^2[ x^2 - 16x + 64] + [ x^2  + 8 ]^2  =  40[x + 1]^2

x^4 - 16x^3 + 64x^2  + [ x^2 + 8]^2 = 40[x + 1]^2

x^4 - 16x^3 + 64x^2 + x^4 + 16x^2 + 64  = 40[x^2 + 2x + 1]

2 x^4-16 x^3+80 x^2+64 = 40 x^2 + 80 x + 40

2x^4 - 16x^3 + 40x^2  -80x +24  = 0

x^4 - 8x^3 + 20x^2 - 40x + 12 = 0

This has no rational solutions

The real solutions are  x = 3 ±√7, y  = 3 -/+ √7

The non-real solutions are x = 1 ± i*√5  , y= 1 -/+ i*√5

i would love to be your friend. :)

I honestly wouldn't care if they called me ugly .. I'd rather people be honest to me then lie .. It won't hurt my feelings.. 

"Don't hate the player, hate the game." - Every asshole ever.

I can hate the player and game right? I can hate Tebow and Football at the same can't I? Same logic here. And if people text you saying you are pretty. Take it. It is a compliment. Take it and increase your self-confidence. Just cause they say you are pretty doesn't mean anything.

Sure... I guess as long as I don't get lied to about that..

I feel your pain, yes indeed i truly do.

put a ???what?

...

if you dont want me to call you pretty, can i at least be your friend? 

Sorry man. I got it simplified down to

1/(sin(x)*cos(x))=cot(x)+tan(x)

Maybe this?

csc(x)/cos(x) = cot(x) + tan(x)  ?

yanderes are great.

how could anyone answer a website!!!!!!!!

Did you forget to add the x variable?

Thanks, dude.