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Let the number=N

5 + 2/3N =N

5 =N - 2/3N

5=1/3N Divide both sides by 1/3

N=15

When a shape gets bigger. (8th grade math, yo)

4! / (57-4)! 4!

I think your "combination" formula should read: 57!/(57 - 4)! 4!=57!/(53! 4!)=395,010

Thank you very much.

but 89 squares each have sides of 5cm are placed on a floor 18.6cm wide and 20.7cm long, how many full squares are used and how many are cut and how many are not used

i get floor area to be 385.02cm squared

It is 10031

The pool is just the volume of a cylinder with a height of 4.5 ft. and radius of 10  ft.

So.......the volume =

pi * r^2 * h  =

pi * [10]^2 * [4.5]  =  450*pi  ft^3

So, the total maintenance cost = cost per cubic ft * number of cubic ft.   =  .75 * 450*pi   =  about  $1060.29

what is 2 * 2

[6 + 2/6]   =    [5 + 1 + 2/6 ] =  [5 + 6/6 + 2/6]   = [ 5 + 8/6 ]

So

[6 + 2/6 ] - [2 + 4/6]  =

[ 5 + 8/6] - [ 2 + 4/6] =

3 + 4/6  =

3 + 2/3

The series is:

Sum_(n=0)^99 (pi i)^n/(n!)=-1.000000000000000000+0.×10^-40i

Here, it is evaluated to 100 terms!. As you can see, the real part is -1 and the imaginary part is tending to zero. Here are the first 10 terms of this series as actually written down:

Sum_(n=0)^9 (pi i)^n/(n!) = 1 + ipi-pi^2/2 - (i pi^3)/6 + pi^4/24 + (i pi^5)/120 - pi^6/720 - (i pi^7)/5040 + pi^8/40320 + (i pi^9)/362880.............etc.
 

Well...you have one problem here.....

The total floor area = 186 * 207 = 38,502 cm^2

But.....the total area of the tiles = 89 * 5 * 5   = only 2225 cm^2

So.....you don't have enough tiles to cover the area no matter how they are arranged

YUSSSSS!!!!

Thanks CPhill 😏😏😏

The answer would then be: 6+6000-322 = 5,684

V = L * W * H

192 = L * 4 * 4

192  = L * 16    divide both sides by 16

12  =  L    [in inches]

2,000,000/15 = 133333.3333333333333333, or simply, 133333 1/3

1.4, or 1 2/5 in simplist form

log(2)+16log(16÷15)+12log(25÷24)+7log(81÷80)

log [ ( 2 * 16^16 * 25^12 * 81^7) / (15^16 * 24^12 * 80^7)]

log [ (2 * 16^16 * (5 *5)^12 * (3^4)^7 ) /  ( (5 *3)^16 * (8 * 3)^12 * (16* 5 ) ^7 ) ]

log [(2 * 16^16 * 5^12 * 5^12 * 3^28) / (5^16 * 3^16 * 8^12 * 3^12 * 16^7 * 5^7) ]

 [log(2) + log (16^16/16^7) + log (5^24/5^23) + log (3^28/3^28) - log(8^12) ]

 [ log (2) + log(16^9) + log(5) + log(1)  - log(8^12)

[ log(2) + log(16^9) + log(5)  - log(8^12 ]

log [ ( 2* 16^9 * 5) / 8^12 ] 

log [ ( 2 * (2^4)^9 * 5)  / (2^3)^12) ]

log [ (2 * 2^36 * 5 ) / (2^36)]

log [2 * 5] 

log 10 

1

4 is the answer, folks.

21

Call the number that Dave has, D

Then Debbie has D- 3

And Will has D/3

And we have that

[D ] + [ D - 3 ]  + [ D/3 ]  = 95      multiply through by 3

3D + 3D - 9 + D   =  285   simplify

7D  =  294    divide both sides by 7

D = 42   = Dave's

D - 3 = 42 - 3  = 39 = Debbie's

D/3   = 42/ 3 = 14  = Will's

And the ratios are

Will :  Dave :  Debbie

14  :    42    :   39

its

10