All Answers 358087 Answers

Let the distance from house to barn be L.  Distance = speed*time, so

L = 300*t1      (1)  where t1 is time to get from house to barn

L = 400*t2      (2)  where t2 is time to get from barn to house

t1 + t2 = 7      (3)

From (1) and (2) we have  300*t1 = 400*t2  so, dividing both sides by 400 we have t2 = 3*t1/4.  Put this into (3) to get:

t1 + 3*t1/4 = 7   or   7*t1/4 = 7  or  t1 = 4

t1 is the time they crawled, so crawling time = 4 minutes. 

This expression factors as  (x - 1)(x + 7)

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Use the calculator here to get

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Triangle area is (1/2)*base length*height.   here: base length = 12 and height = 7.   You can crunch the numbers!

It isn't "in" it is "ln" or "Ln".   "ln" has a lower case "l" not a lower case "i".  It represents logarithm to the base e (e = 2.718281828....)

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How many rgular octagons with an apathum of 1x can you fit in a hexagon with a radius of 5?

You could make estimate it from this....      

Octogons do not tessellate so there will always be holes between the little octogons.

[(4*3.14^2)/((6.673*10^-11)(1.8986*10^27+((1.989*10^30)/2))]*(3.73*10^11)^3

Parentheses didn't look right in the original.Try changing it to this...

[(4*3.14^2)/((6.673*10^-11)(1.8986*10^27+(1.989*10^30)/2)))]*(3.73*10^11)^3

Got 3.078x10¹⁶

What is A and B or C? (hexdecimal to decimal)

\(\begin{array}{|c|r|} \hline \text{hexdecimal} & \text{decimal} \\ \hline 1 & 1 \\ 2 & 2 \\ 3 & 3 \\ 4 & 4 \\ 5 & 5 \\ 6 & 6 \\ 7 & 7 \\ 8 & 8 \\ 9 & 9 \\ A & 10 \\ B & 11 \\ C & 12 \\ D & 13 \\ E & 14 \\ F & 15 \\ \hline \end{array} \)

Line segments are drawn ?

\(X_1, X_2,\ldots,X_9 \text{ are nine points on the circumference of circle } O. \\ \text{Line segments are drawn connecting each pair of points.}\\ \text{How many line segments are drawn? }\)

\(\begin{array}{|c|c|} \hline \text{Points on the circumference of circle} & \text{Line segments are drawn connecting each pair of points} \\ \hline 2 & 1 \\ 3 & 2 + 1 \\ 4 & 3 + 2 + 1 \\ 5 & 4 + 3 + 2 + 1 \\ 6 & 5 + 4 + 3 + 2 + 1 \\ 7 & 6 + 5 + 4 + 3 + 2 + 1 \\ 8 & 7 + 6 + 5 + 4 + 3 + 2 + 1 \\ 9 & 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 \\ \cdots & \cdots \\ \\ n & \frac { (n-1) + 1} {2} \cdot (n-1) = \mathbf{ \frac{n\cdot (n-1) } {2} } = \binom{n}{2}\\ n=9 & \mathbf{ \frac{9\cdot (9-1) } {2} } = \frac{9 \cdot 8 } {2} = 9\cdot 4 = \mathbf { 36 }\\ \hline \end{array}\)

36 line segments are drawn.

it depends on the calculator but usually it's near the \(=\) button. What model calculator are you using?

x^2 * -7 = -7x^2

-7x^2 = x * y

6x = x + y

Therefore, x = 7x and y = -1x.

7   7x   -7

x  x^2.  -1x

   x        -1

The factored form is (7+x)(x-1).

Tafeetoez

8 cavities = 85 minutes

4 cavities = 42.5 minutes

I'm sorry if I'm wrong, use a calculator!

2(4 cavities divided by 2) times 21.25 = amount of time for 4 cavities

pie is 3.14159

The hardest question was the one about erections way back up on the main page... That one's REEEAL hard.

Well, Louise is a dumb b***h for borrowing $750 with fucking %9.5 interest cause this b***h coulda EASILY saved up and bought whatever it was by the end of the SAME FUCKING YEAR. And she woulda paid LESS. LESS. Especially with that retarded a*s %9.5 interest. Problem solved, B***H.