All Answers 358087 Answers

you mean:

Delta price

or

\(\Delta $\)

\(x \Rightarrow \begin{bmatrix} x=-1 \\ x=\pm i \end{bmatrix}\)

potagorean therom.

\(a^2+b^2=c^2\)

\(a^2+o^2=h^2\)

a = a = adjacent

b = o = oppisite

c = h = hypotnuse

yeah you can! it is used al the time! in calculus, limits, derivatives, even in the graph y=tan(x)!

you can use the help station to help you with the fucntions you need.

you mean:

\(f(x)=10x\)

here's the graph:

By using your brain 

100 %   by definition  If the relative humidity is 100%, the dew point is equal to the current temperature

Melody: I just noticed what the problem is with the discrepancy bwtween my answer and Rom's. His equations are just fine.The mistake he made was in substitiution of r1=1/20 into equation 1. He simply made a mistake of getting an answer of 1/10 or 10 days for the second man. From his equation, you get r2=1/30 , or 30 days, NOT 1/10. So his answer is the same as mine. Resolved!!.

P= 2(6+9)= 2(15) = 30

71, also known as "Seventy-one".

I am going to try and adjudicate.    :)

  Two workers, if they were working together, could finish a certain job in 12 days. If one of the workers does the first half of the job and then the other one does the second half, the job will take them 25 days. How long would it take each worker to do the entire job by himself?

Rom says     the workers will take 10days and 20 days to finish 1 job individually

Then if they did half each that would be 5 days and 10 days = 15 days to finish

That doesn't seem right ://

Guest says 20 days and 30 days then that would be 10+15=25 if they do half each.

Mmm if they work together then. Obviously the faster one does more of the job.

\((\frac{1\;job}{20\;days}+\frac{1\;job}{30\;days})*12days\\ =(\frac{1*3\;job}{20*3\;days}+\frac{1*2\;job}{30*2\;days})*12days\\ =(\frac{3\;job}{60\;days}+\frac{2\;job}{60\;days})*12days\\ =(\frac{5\;job}{60\;days})*12days\\ days\;\;cancel\\ =(\frac{5\;job}{60})*12\\ =(\frac{5\;job}{5})*1\\ =1 \;job\)

That is what I need to see.

I am going with our guests answer - sorry Rom.

I think you both did well.  I am going to think about this one some more.

In any given vector space there is only one null vector.In V3r it is (0,0,0).- normally written as a column vector.Think of it as the equivalent of the 'zero'  of the real number system. It is required because clearly,for example, if you subtract a vector from one with its equal and opposite magnitude ,you get the vector equivalent of zero,which needs to be meaningfully represented and to have the same properties as the other vectors in the space.Just as you need zero for numerical and algebraic operations,you need the null vector to be able to carry out a full range of vector operations. 

You can easily check that the null vector obeys the requirement of a vector space,which is simply that   k(a+b)= ka+kb where k is a constant and a,b are any 2 vectors in the given vector space.(You can also easily check that it obeys the dot product.)

A quick proof for the vector space---

Let a,b be 2 linearly independent vectors of a given space.Let the null vector be denoted by 0.

We have k(a+b)=ka+kb.

Then k(a+0) = ka +k0 = ka,since a+0 =a and k0=0

Similarly k(b+0) =kb+k0 =kb,since b+0=b.

and k(a+b+0) =ka+kb+k0=ka+kb,since a+b+0= a+b.

A proof for the dot product is also easy,have a try.

71!! 

I'd like another mathematician to confirm what I have written here please.

MWizzard has asked me to comment on his answer.  (I hope I got your gender right MWizzard       ) 

------------------------------------------

You have said that x/0 is  infintiy but what if is negative then that could not be right.

Basically you simply cannot divide by zero - it is always undefined.

What you can say is :

Find the limit of     6/x      where is is positive but as x tends to 0 then the answer would be +infinity

you would write it like this

\(\displaystyle\lim_{x\rightarrow +0} \;\frac{6}{x}\;=\infty\\~\\~\\ and\\~\\ \displaystyle\lim_{x\rightarrow -0} \;\frac{6}{x}\;=-\infty\\\)

71    

Thank you Melody ! :)

Hi Solveit,

I don't know, sorry ...

When I was very little I rarely made mistakes but I was so slow it was rediculous.

When I got older I had to learn to hurry up and then I made a lot more mistakes.

I am a bit dyslexic so that made it worse too.  

If you have time to check your answers try and check them a different way to how you did it in the first place.

If you go over the same working as before you are likely to overlook the same mistake....

ALWAYS check your answers if it is easy and/or if you have time.

ALWAYS look at your answer and consider if it is reasonable.  eg if you get a probability of 1.5 then you should know it is wrong and you should state that even if you do not have time to redo it.

Sorry, I really do not have anything useful to say.....

MWizard2k04:

This is a primitive problem for any good calculator with a "mod" funtion on it, such as HP calculator that comes with "Windows": remainder of 2^2011/13=2^2011 mod 13=11

Infinity is a "Concept" or an " Idea"!!. You can't do math with an Idea or with Concept!!!.

Transfinite arithmetic is very non-intuitive!   See http://blog.wolframalpha.com/2010/09/10/transfinite-cardinal-arithmetic-with-wolframalpha/ for more details.

0.(6)

You don't list the functions from which to choose!  However, the following should help:

.

No Solutions

Does this make sense to you?

web2.0calc.com/questions/what-is-anything-by-0

Let the number you say, anything, be x.

Now let's test the properties of division (by zero)

Property 1: (for x ≠ 0)

 \(\frac{x}{0} = ∞\)

Property 2: (for x ≠ 0)

 \(\frac{0}{x} = 0\)    

Property 3: (for x ≠ 0)

 \(\frac{x}{x} = 1\) 

However, when x = 0 in all properties,

 \(0 \over 0\)could be infinity (property 1), 0 (property 2), or 1 (property 3).

But, this equation does not make sense, since you cannot share nothing to nobody.

Therefore, there is no solution to \(0 \over 0\)      

Therefore, dividing by zero does NOT make sense at all.

from MathWizard2004 A.K.A. mathw0122

P.S. January 22, 2004 is not my birthday! (gotten from Inside Out)