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Your teacher is dumb. 1+1=2

found it!

a = b(c/b +4) 
a/b = (c/b +4) 
a/b = c/b +4 
a/b -4 = c/b 
c = b(a/b -4) 
c = a -4b

c = 1

Seven times six = fourty two 

lol

The largest doll is 12 inches tall. The height of each of the other dolls is 7/10 the height of the next largest doll and there is 4 dolls?

1- 12 inches

2- 12 x .7=8.4 inches next biggest doll

3- 8.4 x .7=5.88 inches next biggest doll

4-5.88 x .7=4.12 inches the last doll.

Thanks I wanna r8 10 stars!

p= -24 or greater

Solve for x:
x/729+7 = 216 x-9

Put each term in x/729+7 over the common denominator 729: x/729+7  =  x/729+5103/729:
x/729+5103/729 = 216 x-9

x/729+5103/729 = (x+5103)/729:
(x+5103)/729 = 216 x-9

Multiply both sides by 729:
(729 (x+5103))/729 = 729 (216 x-9)

(729 (x+5103))/729 = 729/729×(x+5103) = x+5103:
x+5103 = 729 (216 x-9)

Expand out terms of the right hand side:
x+5103 = 157464 x-6561

Subtract 157464 x from both sides:
(x-157464 x)+5103 = (157464 x-157464 x)-6561

x-157464 x = -157463 x:
-157463 x+5103 = (157464 x-157464 x)-6561

157464 x-157464 x = 0:
5103-157463 x = -6561

Subtract 5103 from both sides:
(5103-5103)-157463 x = -6561-5103

5103-5103 = 0:
-157463 x = -6561-5103

-6561-5103 = -11664:
-157463 x = -11664

Divide both sides of -157463 x = -11664 by -157463:
(-157463 x)/(-157463) = (-11664)/(-157463)

(-157463)/(-157463) = 1:
x = (-11664)/(-157463)

The sign of (-11664)/(-157463) is positive, so (-11664)/(-157463)  =  1×11664/157463:
Answer: |  x = 11664/157463

Yes Alan, I applied the energy equation, but my question was about h = 550 mm is it the pressure head at B? 

And this is how i solve it, maybe its not clear!

(5)/(sqrt(2)-1)

\(\frac{5}{\sqrt2-1}\\ =\frac{5}{\sqrt2-1}\times \frac{\sqrt2+1}{\sqrt2+1}\\ =\frac{5(\sqrt2+1)}{(\sqrt2-1)(\sqrt2+1)}\\ =\frac{(5\sqrt2+5)}{(2-1)}\\ =5\sqrt2+5\)

you are knitting a hat, and you want it to have 3 different colored stripes. you have 6 different colors of yarn.how manydifferent hats could you knit?

I have interpreted this question in the most simple way.

How many ways can I choise 3 colours out of 6.

6C3 = nCr(6,3) = 20

Now I'm confused.

1/20

That was totally awesome! Keep up the good word! Your math teacher would surely appreciate that!

157914976

No comment.

take out battery

Simultaneous equations

\(x^2+3xy+(2y)^2=x^2-xy\qquad (1a)\\ 3xy+4y^2=-xy \qquad \qquad (1b)\\ 4xy+4y^2=0 \qquad \qquad (1c)\\ 4y(x+y)=0 \qquad \qquad (1d)\\ \mbox{True if y=0 and if y=-x}\\ \mbox{solve simultaneously with}\\ 2x+y=12 \qquad \qquad (2a)\\ If\; \;\;y=0 \;\;then\\ 2x=12\\ x=6\\ \mbox{But if y=0 in the first equation then y=0 so this is a nonsense solution}\\ If \;\;y=-x\;\;then\\ -x=-2x+12\\ \mbox{The only solution is (12,-12)} \)

Here is the graph:

The FIRST equation simpifies to:  4xy + 4y^2=0

solve the second for x= 6-y/2    and substitute into the FIRST

4y(6-y/2) + 4 y^2 =0

24y -2^y^2 +4y^2=0

2y^2 +24y = 0

y (2y +24)= 0      so y = 0   or  -12      substitute these values into the second equation to get x = 6   or  12    so x,y  =  (6,0)    or (12,-12)

Hope this helps!

http://www.regentsprep.org/regents/math/algtrig/att2/ltri30.htm

19 baka

oops sorry

can any mods or admins help me delete either one of the two same posts?

oops sorry

can any mods or admins help me delete either one of the two same posts?

4+-1 = 4-1 = 3