Surface area = \(2\times4\times5 + 2\times3\times5 + 2\times3\times4 = 94\)
94 square inches.
n! means factorial n.
which is n(n-1)(n-2) ..... 1
e.g.
10! = 10 times 9 times 8 times ...... times 1
= 3628800
125 x 200
= 125 x 2 x 100
= 250 x 100
= 25000
13, 26, 39, 78
x = 12 + 34
= 46
\(\frac{8}{994} = \frac{4}{497}\)
Here's a possible route (though it could be made shorter):
\(\frac{1}{3}\times(\frac{81\times\sqrt3}{4})\times\sqrt3\times6\)
= \(6\times\frac{1}{3}\times(\frac{81\times\sqrt3\times\sqrt3}{4})\)
=\(2\times\frac{243}{4}\)
=\(\frac{243}{2}\)
Let $x be the tax on $44,500.00.
\(\frac{5.96}{100.00}=\frac{x}{44,500.00}\)
\(x = \frac{(5.96)(44500)}{100}=2652.2\)
The tax on $44,500.00 is $2652.20.
234+356
= 590
What's your question?
100,000,000,000 x 200,000,000,000,000,000
= 1E11 x 2E17
= (1x2)E(11+17)
= 2E28
= 20,000,000,000,000,000,000,000,000,000
It's divisible by 39 or itself
the circumference of the triangle his heads is
A(0.4)
B(10.1
C(1.10)
after running one quarter of a race, wally had to slow down. he ran another fifth of it, and he had to walk the rest of the way. what fraction of the race did wally walk?
\(1-(\frac{1}{4}+\frac{1}{5})\\ =1-(\frac{5}{20}+\frac{4}{20})\\ =1-\frac{9}{20}\\ =\frac{11}{20}\\\)
what is the answer of this q
B= -11/2
C= -5 1/3
\(BC=-1\frac{1}{2}\times -5\frac{1}{3}\\ \mbox{A negative times a negative = a positive}\\ BC=\frac{2+1}{2}\times \frac{15+1}{3}\\ BC=\frac{\not{3}}{2}\times \frac{16}{\not{3}}\\ BC= \frac{16}{2}\\ BC=8\)
how can i get to the number 12 with decimals in two ways?
0.5*24=12
11.6+0.4=12
I have no idea what you are talking about
(3x2 - x2) + (4x3) + (2 - 7)
\((3x^2 - x^2) + (4x^3) + (2 - 7)\\ =3x^2 - x^2 + 4x^3 + 2 - 7\\ =2x^2 + 4x^3 -5\\ = 4x^3+2x^2 -5\\ \)
lolololol bob was here illuminati cnfrmd
Thanks
inverse sine is the same as arc sine. So use [2nd] [asin]
2/y^2 +9/y-7=0
You are lucky to get any help with that opener!
I'd multiply through by y^2 but you need to note that y cannot =0
\(2+9y-7y^2=0\\ 7y^2-9y-2=0 \)
Now just use the quadratic formula :)
