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Observe the pattern: 2,5,8,14,... if the pattern continues, what is the 41st number?

\(\begin{array}{r|r} \hline & \text{Primes of the form 4n-1 } & \\ & p & \frac{3\cdot p - 1}{4} \\ \hline 1 & 3 & a_1 = \frac{3\cdot 3 - 1}{4} =2 \\ 2 & 7 & a_2 = \frac{3\cdot 7 - 1}{4} =5 \\ 3 & 11 & a_3 = \frac{3\cdot 11 - 1}{4} = 8 \\ 4 & 19 & a_4 = \frac{3\cdot 19 - 1}{4} = 14 \\ 5 & 23 & a_5 = \frac{3\cdot 23 - 1}{4} = 17 \\ 6 & 31 & 23 \\ 7 & 43 & 32 \\ 8 & 47 & 35 \\ 9 & 59 & 44 \\ 10 & 67 & 50 \\ 11 & 71 & 53\\ 12 & 79 & 59 \\ 13 & 83 & 62 \\ 14 & 103 & 77 \\ 15 & 107 & 80 \\ 16 & 127 & 95 \\ 17 & 131 & 98\\ 18 & 139 & 104 \\ 19 & 151 & 113\\ 20 & 163 & 122 \\ 21 & 167 & 125 \\ 22 & 179 & 134 \\ 23 & 191 & 143 \\ 24 & 199 & 149 \\ 25 & 211 & 158 \\ 26 & 223 & 167 \\ 27 & 227 & 170 \\ 28 & 239 & 179\\ 29 & 251 & 188\\ 30 & 263 & 197 \\ 31 & 271 & 203 \\ 32 & 283 & 212 \\ 33 & 307 & 230 \\ 34 & 311 & 233 \\ 35 & 331 & 248 \\ 36 & 347 & 260 \\ 37 & 359 & 269 \\ 38 & 367 & 275 \\ 39 & 379 & 284 \\ 40 & 383 & 287 \\ 41 & 419 & a_{41} = \frac{3\cdot 419 - 1}{4} = 314 \\ 42 & 431 & 323 \\ 43 & 439 & 329 \\ 44 & 443 & 332 \\ 45 & 463 & 347 \\ \cdots & \cdots & \cdots \\ \hline \end{array} \)

2.56 x 2^-3=.32 your allowance 3 weeks ago.

Unfortunately, there is no store on the calculator on the home page here.

5.3*10^-5

140  divided by  1 over 4

--->     140  /  (1/4)     =     140 x (4/1)     =     140 x 4     =     560

To divide by a common fraction, multiply by its multiplicative inverse.

Guest's answer and explanation are correct; my approach would be:

Let J represent the number of CDs that Joel has.

Let M represent the number of CDs that Mariella has.

Let B represent the number of CDs that Blake has.

Since Joel has twice as many CD as Mariella has:  

     J  =  2M                  (equation 1)

Since subtracting 7 from the number of CDs Joel has and dividing by 3 equals the number of CDs Blake has:

     (J - 7) / 3  =  B         (equation 2)

Since Blake has 25 CDs, substitute 25 for B into equation (2):

     (J - 7) / 3  =  25

     --->   Multiply both sides of this equation by 3:

     J - 7  =  75

     --->   Add 7 to both sides of this equation:

     J  =  82

So, Joel has 82 CDs.

Now, substitute this value into equation 1:

     82  =  2M

So, Mariella has 41 CDs.

If your allowance double every week, then it was 1/2 as much last week.

Since it is 2.56 now, it was (1/2)x(2.56)  =  1.28 last week.

The week before, it was (1/2)x(1.28)  =  0.64.

And, the week before that, it was (1/2)(0.64)  =  0.32.

So, three weeks ago, it was  0.32.

Theoretical Mathmatics, of course.

Joel has twice as many CDs as Mariella has. Subtracting 7 from the number of CDs Joel has and dividing by 3 equals the number of CDs Blake has. If blake has 25 CDs, how many CDs does Mariella have?

Blake has 25 CDs. By doing the inverse operations, we can figure out how many CDs Joel has. 25*3 is equal to 75, plus 7 equals 82. Dived by two to get the amount of CDs Mariella has, 41 CDs.

2032, and why do you need base-5?

8273892

0.000064

If 1 over 4 is 4 it's 140/4 which equals 35

Thanks alot Alan, You are the best 

zero divided by zero is undefined  !!

5 sqrt(6) + 6 sqrt(4)

\(5 \sqrt6 + 6 \sqrt4\\ =5 \sqrt6 + 6 *2\\ =5 \sqrt6 + 12\\\)

1kg x 2m/s2 = 2 Newtons       (Newtons is a unit of force)

They are already in order so the median is the middle one (or average ofthe middle 2)

8, 9, 10, 10, 10,     11, 11, 11, 12, 13

Median = (10+11)/2 = 10.5

Interquartile range =  11-10 = 1

range = highest score -lowest score

Mean is the average  add them all up and divide by haow many numbers that there are.

Here is a video you can watch about the mean  absolute deviation.

60 seconds in one minute

60 minutes in one hour

5 hours in 5 hours 

so

60*60*5 = 18000

18000 seconds in 5 hours

Yes, fractions are the same as dividing.