\(\left(\sqrt{24}\right)^3\\ =\left ( 2\sqrt6 \right )^3\\ = 2^3\times (\sqrt6)^3\\ =8\sqrt{216}\\ =8\sqrt{6^2\times 6}\\ =48\sqrt6\)
\(\sin 2x = -\dfrac{\sqrt3}{2}\\ \sin 2x = - \sin 60^{\circ} \\ 2x = (180+60)^{\circ}\;or\;2x=-60 ^{\circ} \\ 2x = \dfrac{4\pi}{3}rad\;or\;2x= \dfrac{5\pi}{3}rad\\ x=\dfrac{2\pi}{3}rad\;or\;x = \dfrac{5\pi}{6}rad\)
\(3\tan 2x=\sqrt3\\ \tan 2x = \dfrac{1}{\sqrt3}\\ 2x = \dfrac{\pi}{6}rad\;or\;2x=\pi + \dfrac{\pi}{6}=\dfrac{7\pi}{6}rad \\ x=\dfrac{\pi}{12}rad\; or\; x= \dfrac{7\pi}{12}rad\)
You can imagine that 2 minus signs crossed together is the plus sign.
6- (-4)= 6 + 4 = 10
59 or 60. Depends on the date.
If you were born on 5 July 2002 and you will be 59 years old in 1 July 2062
If you were born on 5 July 2002 and you will be 60 years old in 1 August 2062
Understand?
Help nows or in the tomarow after today
The second hand will turn 60 rounds per hour.
Length of each round = 60.72/60 = 1.012m = 101.2cm
Circumference = 2(pi)(radius)
Let rcm be the length of second hand
101.2 = 2(pi)(r)
r = 101.2/(2pi)
Use the calculator for it ;D
\(\left(\dfrac{s^6d}{rt^7}\right)^{-8}\\ = \left(\dfrac{rt^7}{s^6d}\right)^8\\ = \left (\dfrac{r^8t^{56}}{s^{48}d^8} \right )\)
That could not be further simplified.
Guest #2's answer means
\(\begin{array}{rlll}&-&5&.9\\-&&8&.2\end{array}\)
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Yay time for the rescue!!
\((x-9)^2=49\\ \sqrt{(x-9)^2}=\pm \sqrt{49}\\ x-9 = \pm 7 \\x = 16 \;or\; x = 2\)
Check: (16-9)2 = 72 = 49
(2-9)2 = (-7)2 = 49
ask maxwong
maxwong answer me plz
Whoops I don't need the partial fraction decomposition.
i can help you here is some ex
4*3=12 add 4 3 times
\(7\times 2 = \underbrace{7+7}_{2 times}=14\\ 7\times 9 = \underbrace{7+....+7}_{9 times}=63\)
thx guys
Compute the partial fraction decomposition of the following: 1/(s^2-1) Factor the denominator into linear and irreducible quadratic terms: 1/((s-1) (s+1)) Then the partial fraction expansion is of the form: 1/((s-1) (s+1)) = θ_1/(s-1)+θ_2/(s+1) Multiply both sides by (s-1) (s+1) and simplify: 1 = θ_1 (s+1)+θ_2 (s-1) Expand and collect in terms of powers of s: 1 = θ_1-θ_2+(θ_1+θ_2) s Equate coefficients on both sides, yielding 2 equations in 2 unknowns: 1 = θ_1-θ_2 0 = θ_1+θ_2 In matrix form the system is written as: (1 | -1 1 | 1)(θ_1 θ_2) = (1 0) In augmented matrix form, the system is written as: (1 | -1 | 1 1 | 1 | 0) Subtract row 1 from row 2: (1 | -1 | 1 0 | 2 | -1) Divide row 2 by 2: (1 | -1 | 1 0 | 1 | -1/2) Perform back substitution on the augmented upper-triangular matrix: (1 | -1 | 1 0 | 1 | -1/2) Add row 2 to row 1: (1 | 0 | 1/2 0 | 1 | -1/2) Read off the solutions: θ_1 = 1/2 θ_2 = -1/2 Therefore: Answer: |1/(s^2-1) = 1/(2 (s-1))-1/(2 (s+1))
Line them both underneath each other like:
-59
-82
Then you add 9 by 2 then you add 5 by 8 and add the top number to the left one. After you find the answer, you find out how many places there are after the decimal to both of them. You will find out that there are two places. So on our answer we will move the decimal to the left twice and then you have your answer.
Let $x be the original price.
(1- 20%)x = 46
80%x = 46
0.8 x = 46
x = 46/ .8 = 460/8 = 57.5
The original price is $57.5
Do your teacher mean 'Round to 2 decimal places if necessary' ? Because I see that you don't need to do that.
\(-5.9+-8.2\\ = -5.9-8.2\\ = - (5.9 + 8.2)\\ = -14.1\)
That's a question that our calculator can do :D but I do it all by myself.
Let x ft be the width of the rectangle.
P = 2(x+x+6) = 2(2x+6) OR 4(x+3) OR 4x+12 depends on what your teacher wants you to do.
\(4.7 + 1\dfrac{7}{10}\\ = 4.7 + 1.7\\ = 6.4\\ \mbox{OR}\\ = 6\dfrac{2}{5}\)
Thanks to webpages. Now I know that \(L[\sinh t]= \dfrac{1}{s^2-1}\)
\(-7+(-3\dfrac{2}{5})\\ = -7-3\dfrac{2}{5}\\ = -10\dfrac{2}{5}\)
