All Answers

+3146

[input]1454 * 3.6%[/input]

adminMay 31, 2012

+3146

[input]((1.16840)^(1/5))-1[/input]

adminMay 31, 2012

2/3+5/6=?

2 * 2 = 4
_ _ _ 4/6 + 5/6 = 9/6 = 1 3/6 = 1.5
3 * 2 6

5 * 1 = 5
_ _ _
6 * 1 = 6

GuestMay 31, 2012

What?

GuestMay 31, 2012

Guest:
2/3+5/6=

2/3+5/6=1.5

GuestMay 31, 2012

+3146

[input]plot( 2x )[/input]

adminMay 31, 2012

+3146

Flexography:
x = 33.3

nice.

[input]5(X-31)=11.5[/input]

adminMay 31, 2012

+30

...
so what's your question..?

FlexographyMay 31, 2012

+30

225cm^3 = 1/3*pi*r^2*5
= 225/(1/3)/(pi)=r^(2.5)

[input]225/(1/3)/(pi)=r^(2.5)[/input]

FlexographyMay 31, 2012

+30

(10x^2-11x-6)
= (2X - 3)(5X + 2)

FlexographyMay 31, 2012

+30

[input]3^3.1[/input]

FlexographyMay 31, 2012

+30

-5(X-31)=11.5
x-31 = 11.5/(-5)
x = 31 + 11.5/5
[input]x = 31 + 11.5/5[/input]
x = 33.3

FlexographyMay 31, 2012

May 30, 2012

+3146

[input]f(t)=476-4.9t; f( 3 )[/input]

[input]plot( 476-4.9t, t=0..100 )[/input]

adminMay 30, 2012

+30

Quote:
Solve: (1/3)^x = sqrt(27^6)

I can't find past complete examples in my book & I'm studying for my exam... any help would be appreciated!

It's important to note what a square root represents.
A 'square root' is the same thing as the exponent (1/2)!

Let us rewrite the above equation:
(1/3)^x = (27^6)^(1/2)
(1/3)^x = 27^3
The left side is a fraction. To make it a whole number, the power must be negative ( x < 1 ).
Now we need to determine what that exponent is:
(1/27)^x = 27^9
(27/1)^-9 = 27^9
Therefore, x = -9

That way, with numbers as simple as this, you can really think it through (you don't really need to do all the steps, you can probably do it in your head, but with different numbers you might have to do some more work.

There's a much easier way to solve this problem, and that is using Logs.
If you don't know what a Logarithm is, it's an exponential scale (instead of counting like 1, 2, 3, 4 or like 10, 20, 30, 40, you are instead going like 10^1, 10^2, 10^3, 10^4)
Logs allow you to work directly with the exponents.
To solve this with logs we would do this:
(1/3)^x = (27^6)^(1/2)
(1/3)^x = 27^3
Log1/3(27^3) = x
x = -9

FlexographyMay 30, 2012

+35

MathiMay 30, 2012

+30

Let the total cost of foundation contribution equal X

Person A = Half of X
Person B = An eighth of X
Therefore
PersonA + PersonB = (1/2)X + (1/8)X
(1/2) = (4/8)

(4/8)X + (1/8)X = (5/8)X

If X is the total, then
X - (5/8)X = the remaining amount
Therefore the unfunded portion = (3/8)X, three eighths of the money.

FlexographyMay 30, 2012

+30

I'm not familiar with the term 'continuously', but I'm going to assume that it means 'daily'.

When you are looking at compound interest, words like 'quarterly' are referring to the frequency of compound periods in a year (how often interest is added to your principal).
Interest, in compound interest calculations, is divided by the compound frequency (assuming your interest % is an annual rate).

Annually --> Once per year. i/1
Semi (Semi-annually) --> Twice per year. i/2
Quarterly --> Four times a year. i/4
Monthly --> Twelve times a year. i/12
Biweekly --> 26 times a year. i/26
Weekly --> 52 Times a year. i/52
Daily --> 365 times a year. i/365

Similarly, you could be given a more specific number of compound periods (eg: 98 times a year) in which case you would simply divide the interest rate by the specified value.

So, if you have $1000 and are given a 5%/a interest rate, compounded monthly for 10 years, you have:
[input]A=1000(1+0.05/12)^(10*12)[/input]

FlexographyMay 30, 2012

+3146

[input]16*pi*e[/input]

adminMay 30, 2012

+3146

adminMay 30, 2012

+3146

123:
(x-y) + 1

almost..
x=5
y=4
(x-y) + 1 = (5-4)+1 = 2

but:
x=4
y=5
(x-y) + 1 = (4-5)+1 = 0 (not correct)

modified formula:
abs(x-y) + 1

x=4
y=5
(x-y) + 1 = abs(4-5)+1 = abs(-1) + 1 = abs(1) +1 = 2

adminMay 30, 2012

(x-y) + 1

GuestMay 30, 2012

May 29, 2012

+3146

[input]-3/4b-5=31[/input]

adminMay 29, 2012

+3146

[input]int( ((sqrt(x)-1)^3)/x, x )[/input]

adminMay 29, 2012

+3146

[input]-1 / 15 + 8 / 9[/input]

adminMay 29, 2012

+3146

[input]2^3[/input]
(=2*2*2)

adminMay 29, 2012

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