All Answers 354591 Answers

Oh wow... Im bad. Ment x= 4 or x= - 0.8 ...

im just going to sleep cant think straight anymore

Well I made a mistake in the calcuation above. Everything starting from the part where I assume IxI is negative is wrong.

IxI.  =. 2/3x. + 4/3

This is correct if x=8 or x= -0.8

IxI.  = 2/3x + 4/3 is true when

x = 2/3x+4/3 or x = -2/3x -4/3

Dont know how to calculate those though. 

bigger and stronger bbs.

Hey....I thought that was pretty good.......HEHEHEHE!!!!

Oh Chris, your joke is soooo corny (or is that chalky, like plaster?).    :) 

LOL  What do you think Ginger.  Can Max be your snap?

From drunk parents in France.......

Haven't  you ever heard of the "Plastered" of Paris  ??"

Maybe Max can be a "Ginger" Snap......

something like the distance between earth and the sun, eh?

x^2 - 3|x| + 4 = 0

I don't  believe this has any "real" solutions......

See here :  https://www.desmos.com/calculator/pvwvwzobj7

5m+-1=-1t5m what is m

\(5m+(-1)=-115m\)        [ + 115 + 1  on both sides

\(120m=1\)                               [ / 120   on both sides

\(m=\frac{1}{120}=0.0083\overline3\)     !

lol

Actually 99! is 1*2*3*4*5....*99

So 99! is some long number I dont want to copy paste. Just try it on the calculator up there on the home button. Yw

or you just take it as guest1 said.

99 is a number 

! Is an exclamation point

burn

Yep Chris is right too but if my way can be used to answer a multiple choice question (as you implied it was) even if the function is difficult to factor :)

My way is always easy :)

Hey Rosala, 

Did you see this post from yesteday..

F(x)=x^3+3x^2+4x+12

Factor to  find the roots

x^2(x + 3) + 4(x + 3)  = 0

(x^2 + 4) (x + 3)  = 0

Set the factors to 0

x^2 + 4  =0                    x +  3  = 0

x^2  = − 4                      x    =  − 3

x = ± i√ 4

x = ± 2i

So.....the roots are ± 2i  and − 3

g(2)=9

f(9)=2

f(g(2)=f(9)

f(9)=2

Yes Rosala,

Guest thought it was amusing that he/she was drinking fake champagne :)

Adults often celebrate such occasions with real champagne :)

Hi Rosala,

It is always great to see you on the forum and I hope that 2017 is a great year for you!

I was chatting on line and posting a "Happy New Year" message on the forum at about that time on New Years Eve.

I was also listening to a New years eve concert on tele and feeling content and happy :) 

which of the following is a root of the polynomial function? F(x)=x^3+3x^2+4x+12

Your question is not complete but it doesn't matter.

IF the number a is a root then  f(a)=0

Oh! So inspirational! Tears come to my eyes!

I think the answer to this question is :   ∅     (null)