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The answer is 728

R   = cloud rats                           2

(3/2)R  = guinea pigs                  3

(3/2) [(3/2)R]  = hamsters           9/2   

So...since we can't have 9/2  hamsters.....we need to multiply by 2

R   = cloud rats                        2  * 2   =  4

(3/2)R  = guinea pigs               3  * 2  =   6

(3/2)(3/2)R  = hamsters           9/2 *2  =  9

So...the smallest that N  can be =  4 + 6 + 9  =  19 

Yep, guest is right, I cant add up properly LOL

9+4+6=19  !!

Thanks guest ;)

Given your problem, we need to set up a price per cat. If 12 cats costs $989687356656310605403, then each cat costs 

989687356656310605403/12 = $82473946388025883783.583333333. Therefore, if you want to find the price of X cats you simply multiply the price of one cat times X. 

(eg) 25 cats costs $82473946388025883783.583333333*25 = $2,061,848,659,700,647,094,589.58 or 2 sextillion USD which is more money than all of the money in all of the worlds economies combined. Man those are expensive cats!

2)

\(f(x)=3x-1 \qquad g(x)=x-1\qquad find (f \circ g)(x)\\~\\ (f \circ g)(x)=f(g(x))=f(x-1)\\ \text{So replace the x in the f function with (x-1) }\\ f(x-1)=3(x-1)-1=3x-3-1=3x-4\\ (f \circ g)(x)=3x-4 \)

From your problem, we can represent the number of hamsters, guinea pigs, and giant cloud rats with the letters H, G, and R respectively. Therefore, the following equations are true:

2H = 3G

3R = 2G

N = R + G + H

Now we can solve for R and H in the upper equations with respect to G and substitute them into the lower equation:

H = 3/2G

R = 2/3G

N = 2/3G + G + 3/2G

Simplifying gives: 

N = 19/6G

Since N must be a whole number, G has to be a multiple of 6 for this equation to make sense. Therefore, we will use 6 for G to find that N=19. 

Checking your work will indicate that there are 6 Guinea Pigs, 9 Hamsters, and 4 Giant Cloud Rats, and this is indeed the smallest combination of the three with all else being true. 

I have set up the 2 ratios here.  You must keep the same ratios but make the number of guinea pigs the same.

The lowest common multiple of 2 and 3 is 6

So this is the ratio of the animals

The number of animals in total is a multiple or 18.  The smallest number is 18    :)

We know these points  ( 12, 0) , (9,6)  and the parabola will open downwards

And the verex will be at the max height, h......let  the vertex  = (0, h)

So we have

y  =  −ax^2 +  h    using the points  we have

0  = −a(12)^2 +  h    →  0 =   −144a +  h       (1)

6 =   −a(9)^2 +  h     →  6 =   −81a +  h         (2)

Subtract   (1) from (2)  and we have

6 = 63a        solve for a

6/63  = a  =  2/21

Find h  using ( 1)

0 =   −144(2/21) +  h 

144(2/21)  = h

288/21  = h

h  = 96/7 m  ≈  13.71 m

Here's a graph:  https://www.desmos.com/calculator/a06alawmri

15  

(a) Area  =    L * W   =  (x + 2) ( x + 1)   = x^2 + 3x + 2

(b) Assuming this is a right triangle....find x     ....

x^2  + (x + 3)^2   = 225

x^2 + x^2  + 6x + 9  = 225

2x^2 + 6x −216  = 0

x^2 + 3x − 108  = 0

(x + 12) (x − 9)  = 0    →   set both factors to 0 and solve   x  = 9    or  x = −12 [reject]

So

Area = [B * H] / 2  =  [x (x + 3)] / 2  =  [ 9 ( 9 + 3)] / 2  =  [9 * 12] / 2  =  108 / 2  =  54  units^2

16 

f(x)  = x^2 − 7x + 3       take 1/2  of 7 = 7/2  square it   = 49/44   add it and subtract it

f(x)  = x^2 − 7x + 49/4  + 3   −  49/4     factor the first three terms and simplify

f(x) =  ( x − 7/2)^2  + [ 12 − 49] / 4

f(x) =  ( x − 7/2)^2   − 37 / 4

29030400

Add up all the numbers you have, then divide the total by the number of numbers you added up. For instance...

I want to find the average of 45, 32, and 27.

First, I add up all the numbers. (the total is 104)

Now, I divide this total by the number of numbers I added up. (I added three numbers)

I divide 104 by 3, and I get thirty-four and two-thirds as my average.

Cos= Adjacent side over the Hypotenuse 

Sin= Opposite over the Hypotenuse 

Tan= Opposite over the Adjacent  

cos=a/h 

sin=o/h 

tan=o/a

I'm sorry.....what angle are you given... and WHICH side length?

I am thinking it MIGHT be   TAN (angle) = OPPOSITE/ADJACENT      

Good Luck !

What is the SHAPE of the tunnel......TRIANGULAR?     A tunnel has a_________ cross section????

I think it's just 20

100*2-300+100+10+15-23=2 (1+1=2) 

Q=19

2+5=x 

2+5=7 

7=x 

4-2=2  

2-0.42=1.58 

Therefore the answer is 1.58

10.

Proof: 8=6+2

8/0=(6+2)/0

8/0 * 0 =6+2

0=6+2

-2=6

Plug into the questioner's expression

8-(-2)=

8+2= 10 

Think of it like this, 5.00/2=2.50 ok then 7.50/3=2.50 then 12.50/5=2.50 then 20.00/8=2.50 so the answer is c=2.50n.

Just divide the amount of money by the amount of cards, and that should get you your answer. c=2.50n because it is 2.50  (c) for ever greeting card (n)