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Solve for x over the real numbers:
9^(3 x) = 4^(7 x + 3)

Take the natural logarithm of both sides and use the identity log(a^b) = b log(a):
6 log(3) x = 2 log(2) (7 x + 3)

Expand out terms of the right hand side:
6 log(3) x = 14 log(2) x + 6 log(2)

Subtract 14 x log(2) from both sides:
(6 log(3) - 14 log(2)) x = 6 log(2)

Divide both sides by 6 log(3) - 14 log(2):
Answer: |x = (6 log(2)) / (6 log(3) - 14 log(2))

∑[2k+5], k=1 to 200   [Is this what you mean?] If yes, then we have:

∑[2k+5], k=1 to 200 =41,200.

fish

Jacob must be snowwolf then hes been gone for ages and has aded in drama

Well that sounds like a personal issue

You blocked. Me XD i just realized that XD 

Very salty.

Ck his a*s batman

XD for grayson

So this is Cole?

Thats why he's salty ok

XD wow

Convert 2% to a decimal

2% = .02

.02 x 6975 = 139.5

You put a star then theres a flag below it :P

He is 😵  I never knew no joke

Let N be the number...so we have

N^(1/2)  = 2N^3  rearrange as

2N^3  - N^(1/2)  = 0    factor

N^(1/2)  (2N^(2.5) - 1)  = 0      set each factor to 0

N^(1/2)  = 0    →   N  = 0  [ reject.....0 isn't positive...]

And

2N^(2.5) - 1  = 0       rearrange

2 N^(2.5)  = 1         divide by 2

N^(2.5)  = 1/2    →  N  = (1/2)^(1/2.5) =  (.5)^(0.4) ≈  .75786

NIce try Cole we know that you Tyla.Fox Emerson Mcloughin and Cole_2 are the same person

It  means "no  solution "

To solve this problem, you must isolate the variable on one of the two sides, preferably the left side.  To do so, you must look at the equation.  Is the side with the variable in that expression adding or subtracting the 52?  It's adding it, so you must do the inverse, or opposite, of addition to both sides.  This will leave you with 2x=47.  From here, you must keep up the habit of doing the same thing to both sides, and you must isolate the variable yet again, so this time you must do the inverse of division to isolate your variable.  2x/2 and 47/2 will in the end product give you x=23.5.

one more chance what type of chance