Speed =Distance/Time
Let the distance travelled before the 2 trains meet=D, then
D/85 =[D+46]/110, solve for D
D =156.4 miles - when the 2 trains will meet.
156.4/85 =1.84 hours- after 3:30 when they will meet, or 110.4 minutes after 3:30pm. So that:
3:30 + 1.84 =5:20:24pm - when the 2 trains will meet.