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subtract the -9 from both sides and then divide by 8 on bothe sides to get 23 = x

gg

If your wanting 4GB, yes you will need an upgrade of power supply, because the current power supply you have right now may not support a new number of GB, and for your sake I would not risk your upgrade process failing due to too low power supply. 

Hope this helps!! 

Yes it does you could even make the arithmetic equation of this. Say you have a volume of 5 (units) in the cylinder...

if you keep taking down the volume by 1/4 then it decreases by a common amount each time.

l'll even write out a sequence.

5, 19/4, 18/4, 17/4...

l'm sure you can figure the arithmetic for this, if not, let me know c:

Solution for original velocities of father & son, via kinetic energy

\(\text {(a)}\\ \small v_f \small \text { velocity of father. } v_s \text { velocity of son. } \\ \frac{1}{2} m_f(v_f + 1.0)^2 = 2 × ½ m_fv^2_f \\ (vf + 1.0)^2 = 2v^2_f \\ v_f +1 = \sqrt{2}v_f \hspace{3em} \text { | square root of both sides}\\ v_f + 1 \approx 1.4142v_f \\ v_f \approx 2.4143v_f \\ 0.4142v_f \approx 1 \\ v_f \approx 1.4143 \\ \text { } \\ \text {(b)}\\ \frac{1}{2}v_s^2 = 2 * \frac{1}{2} (m_fv^2_f) \\ \frac {1}{4}v_s^2 = v^2_f \\ v_s^2 = 4v_f^2\\ v_s = 2v_f \approx 4.8286 m/s \)

\(\small \text{Theory & Formulas: Complements of Gottfried Wilhelm Leibniz, with Christiaan Huygens & René Descartes. }\\ \small \text{ }\hspace{17em}\scriptsize \text {(Amazingly, there is very little of Sir Isaac Newton in this.) }\\ \small \text{Produced by Lancelot Link and company. }\\ \small \text{Directed by GingerAle. }\\ \small \text{Sponsored by Naus Corp. Tortoise and Hair Dye: }\\ \small \text{ }\hspace{9em} \small \text {Artificial intelligence formula for slow blondes and some mathematicians. }\\ \small \text{ }\hspace{9em} \small \text {New formula now works for red-heads. } \scriptsize \text{(Helps to prevent communist sympathies, too.) } \)

Well, you should know this fact:

1 kg =1,000 g. So, if you had 625 grams, what does it equal in kg?

Just divide =625 g /1,000 g =0.625 kg.

Is this what you mean? Example: 0.25% =0.25/100 =0.0025. This is the correct way.

150% =150 / 100 = 1 1/2 =3/2 =1.5

Thank you 

JayClan? what's that? 

.22% =0.22 / 100 =0.0022 = ~9 / 4091.

22/10000, or 11/5000

{27 x 26 x 25 x 24 x 23..........} / {23! x 4 x 3 x 2 x 1} =17,550

      ∫ x^2 dx = x^3 / 3 + Constant.

9/54 = 1/6

1/6 = 0.1666666666666667

Remember SOH/CAH/TOA (Sin when Opposite over Hypotenuse, Cos when Adjacent over Hypotenuse, and Tan when Opposite over Adjacent) in sin A the opposite is 48 and the hypotenuse us 50, so sin A = 48/50, and in cos A the adjacent is 14 and the hypotenuse is 50, so cos A = 14/50. Your answer is B: sin A = 48/50, cos A = 14/50

log_b a in correct format on this calculator is

log(a, b)

Mayberry Textiles Inc. is considering the purchase of a new machine which has an initial cost of $400,000. Annual operating cash inflows are expected to be $100,000 each year for eight years. No salvage value is expected at the end of the asset's life. Mayberry's cost of capital is 14 percent. Compute the net present value of the machine. (Ignore income taxes).

First, you have to find the PV of the 8 cash inflows @ 14% using this formula:

PV=P{[1 + R]^N - 1.[1 + R]^-N} R^-1

PV =100,000 x {[1.14]^8 - 1 / [1.14]^8 / 0.14}

PV =100,000 x                  4.63886389.....

PV =$463,886.39 - This is net PV of the 8 cash inflows.

Second, you subtract the initial cost of $400,000 from above PV.

$463,886.39 - $400,000 =$63,886.39 - This is the "Net Present Value of the Machine".

a. Angle H is congruent to Angle B

b. GH/DJ = AB/DC

sqrt(94) = 9.695359714832658​

3.14 * 8888888898888888888888888999988888880 = 27911111142511111111111111459965111083.2

666/666*666/666*666

1*666/666*666

666/666*666

1*666

666

The fraction bar is / on your keyboard.

E=mc² is an equation representing mass-energy equivalence. This means that anything having mass has an equivalent amount of energy, and vice-versa (the other way is correct as well).

The variable E represents energy

The variable m represents mass

The variable c represents the speed of light constant.