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ah so it went from 100% to 98% because of the 2% drop

and I see.

I actually rounded the decay factor....if you use -.0202, you get

.928M * e ^(-.0202 * 40)   =  .413655  which is close to .414

If something drops 2% from one year to the next....it's only 98% of what it was the year before....does that make sense???

C. was wrong,

but I did .928*.98^40= .414 which was correct

I dont understand how you got "98%"

Can you show me an equation on how you got that.?

nope i got no answer for you

(a) Call the number who married in 1960 = M

And.....5 years later......the number who remained married = .928M

And we have that one year later 98% of these remain married....so.......  0.98 (.928M)  = .90944M

So

.90944M  =  .928M*e^(k * 1)   divide by M

.90944 = .928*e^(k)    divide by .928

.90944/.928  = e^(k)     take the ln of both sides

ln (.90944/.928) =  ln e^(k)

k = ln (.90944/.928)  = -.02  = the decay factor

(b)  The function is .928M * e^(-.02n)     where n is the time in years since the 5th anniversary

(c) 45 years later we have

.928M * e ^(-.02 * 40)  ≈ .417M   [about 41.% remain married ]

You have 8/8 of an apple.

help !!! lol

Bios.......!!!!

Hello guest,

You are very polite.  I'd like you to become a member :)

\(y=\frac{1}{2}sin(2x+3\pi)\\ \text{Here is the trick }\\~\\ y=\frac{1}{2}sin[2(x+\frac{3\pi}{2})]\\ amplitude =1/2\\ period=\frac{2\pi}{2}=\pi\\ Phase \;shift=\frac{3\pi}{2}\;\;left\\ \text{Since the period is pi, this is 1.5 wavelengths}\\ \text{So it will still start at (0,0) but it will start going down instead of up.} \)

Here is the graph:

Use the following equation:

\(p={100*(c/q)}\)

p = percent of questions correct

c = questions answered correctly

q = overall number of questions

For example, if you got 12 questions correct out of 19-

\(p = {100*(12/19)}\)

\(p = {100*(.632)}\)

\(p = 63.2\)

You would get a 63.2%

"lol" can be simplified to the following:

\(lol = {l^2o}\)

-3 + 2 / 3 * -4 + 1 / 2

-3 + (2/3) * -4 + 1 / 2

-3 - (8/3) + 1 / 2

-3 - (8/3) + (1/2)

-(18/6) -(16/6) + (3/6)

(-31/6)

Answer- \(\approx 5.17\)

EDIT:

7 out of 18 in the class are boys...

so 11 out of 18 are girls

11 is to 18   as  49 is to 'x'      where 'x' is the total number of boys and girls

11/18 = 49/x

x = 49 x 18/11 = ~80 total

49 girls    ~~ 31 boys

To use a fraction in the calculator, simply put it in parentheses.  For example, one half could be written- (1/2)

Setup Ratio-

7 boys : 11 girls

x boys : 49 girls

Cross Multiply-

7*49 = 11x

Simplify-

343 = 11x

Divide-

343/11 = 31.18

Answer-

About 31 boys

I'm not sure, : / 

Why do you ask

How do you write -5/2 over 1 as a fraction

\(\large \frac{\frac{-5}{2}}{1}=-\frac{5}{2}\)

  !

Ok I don't know if you will see this, but I just realized that the answer I gave you was probably wrong because I forgot that some places use " . " as a seperator for thousands, not a decimal. In the rest of this post, I will just put spaces to separate thousands to avoid confusion.

actual area of the lake = 18 000 000 square meters

actual area of the lake = 18 000 000 / 1000² square kilometers

actual area of the lake = 18 000 000 / 1 000 000 square kilometers

actual area of the lake = 18 square kilometers

map area of the lake = 18 / 2² square cm

map area of the lake = 18 / 4 square cm

map area of the lake = 4.5 square cm         <---(That " . " is a decimal)

Rise / Run  x 100%

You would need to know the volume, V, then the mass will be V/v. (v is specific volume)

.