All Answers 358116 Answers

I checked your answer,

seems correct to me, but I'm no genius in this field of expertise.

I also googled it to be sure and the problem has been used a million times only with different numbers.

"Is" means  '='

"Of" means "multiply"

32% = .32

"What"   = x

So we have

43.7 = .32*(x)     divide both sides by .32

43.7 / .32 = x  = 136.5625

And there's the answer

You need to give a little more information Carol.

CPhill has guessed what you want and he is most likely correct but what does PMT stand for.  

Not everyone around uses the same letters or acronymes for a particular meaning.

This is obviously a present value question but is it for an ordinary annuity or for an annuity due?

CPhill has assumed ordinary annuity because this is the most common.  

He probably guessed correctly.

Thanks Chris.

I thought I could let wolframalpha check it for you.

Maybe I overestimated a little;

now I need to work out what Diane's new repayments will be if her interest rate drops to 4%

30 years is remaining on the loan.

This is the present value of an ordinary anuity so you will use this formula (same formula)

$$A=R\times \frac{1-(1+i)^{-n}}{i}$$

A=285308.73

R=$??

i=4%/12=0.3repeater%=0.003333333....

n=30*12=360 months

$$\begin{array}{rll}
285\;308.73&=& R\times \frac{1-(1.00\dot3)^{-360}}{0.00\dot3}\\\\
285\;308.73&=& R\times 209.4612296\\\\
R&=&\$ 1362.11 \mbox{ to the nearest cent}
\end{array}$$

------------------------------------------------------------

So her payments dropped from $1710.57 to $1362.11

$${\mathtt{1\,710.57}}{\mathtt{\,-\,}}{\mathtt{1\,362.11}} = {\mathtt{348.46}}$$

This would save Diane $348.46

------------------------------------------------------------

Now all of this is assuming that I have made no careless mistakes.

At least the numbers pass the sensibleness test (I think)

Now, please tell me if you have the answer in the back of a book or somewhere.

NOW you will need to work out the present (5years down the track) value of the loan

This is the present value of an ordinary anuity so you will use this formula (same formula)

$$A=R\times \frac{1-(1+i)^{-n}}{i}$$

A=??

R=$1710.57

i=6%/12=0.5%=0.005

n=30*12=360 months

$$\begin{array}{rll}
A&=& \$ 1710.57\times \frac{1-(1.005)^{-360}}{0.005}\\\\
A&=& \$ 1710.57\times 166.79161444\\\\
A&=&\$ 285\;308.73 \mbox{ to the nearest cent}
\end{array}$$

------------------------------------------------------------

So after 5 years Dianne owes the bank $285 308.73

LOL!!!....I loved that last one...!!!

Well done, reinout !!

Here's the way I like to think about this sort of problem. Each day the man drinks 1/20 of the cask. When his wife helps him, they drink 1/14 of the cask each day. So 1/14 - 1/20 must be the portion that she drinks everyday.

1/14 - 1/20   = 6/280  .......  now, just take the reciprocal of the fraction on the right

280/6 = 46+2/3 days

And there you go.....

i loved the last one the most !thanks for them reinout! thumbs up!

I am going to answer this in a series of posts because it is long and I am going to have to do some homework along the way

FIRST

first you will need to find the initial repayments.

This is the present value of an ordinary anuity so you will use this formula

$$A=R\times \frac{1-(1+i)^{-n}}{i}$$

A=300000

i=6%/12=0.5%=0.005

n=35*12=420

$$\begin{array}{rll}
300000&=& R\times \frac{1-(1.005)^{-420}}{0.005}\\\\
300000&=& R\times 175.3802262\\\\
R&=&\$ 1710.57 \mbox{ to the nearest cent}
\end{array}$$

Okay now I have to work out how to find the amount that will still be owing after 5 years.

Do you have an answer already and want to know how to get to it?

If so, can you post the answer in please? 

(1nanometre = 10^-9 metres ) 

1nm = 10^-6mm

so

32nm

=32*10^-6mm

=3.2*10^-5mm     (this is in scientific notation)

= 0.000032mm

You have 2 variables and only one equation so you cant solve it.

What is it that you want us to do with it?

     Okay my favourite is a toss up between y u no find x  and the last 'fish' one.   

Friday 20/6/14

Lunch box unwrap - Examples of memes.  (Thanks reinour-g)

Yes yes, very clever anonymous.  

There is a well known proverb that one can lead a horse to water, but you can’t make him drink.

Francis says this is true. He also pointed out, that you can lead a horticulture, but you can’t make her think.

I can't even make a thirsty horse drink from a trough.

I tell you, everything is four!

For example CPhill, has six letters, six had three letters, three has five letters and five has four letters.

reinout has seven letters, seven has five letters and five has four letters.

Supercalifragilisticexpialidocious has thirty-four letters, thirty-four has ten letters, ten has three letters, three has five letters and five has four letters.

Thank you, Melody

Heureka's answer demonstrates that if you are a student with an ordinary hand held calculator that this expression cannot be factorised.    It only has 1 real root and that is x approx equal to 1.6

For those who don't understand why heureka manipulated reciprocal times (which is the correct thing to do) here's a more long-winded approach.

$$\dfrac{1}{20}+\dfrac{1}{x}=\dfrac{1}{14}$$

$$\dfrac{1}{x}=\dfrac{20-14}{14*20}=\dfrac{6}{14*20}$$

$$x=\dfrac{14*20}{6}=46.6666666667$$ 

for the wife alone 46.6666666667 days

P.S.

$$\begin{array}{lcr}
\frac{1\;V}{20\;days} & \mbox{rate for 1 day} & \mbox{man}\\\\
\frac{1\;V}{x\;days} & \mbox{rate for 1 day} & \mbox{woman}\\\\
\frac{1\;V}{20\;days} + \frac{1\;V}{x\;days} & \mbox{rate for 1 day} & \mbox{man and woman}\\\\
\left(\frac{1\;V}{20\;days} + \frac{1\;V}{x\;days}\right) & \times \mbox{ 14 days}
&=1\mbox{ V}
\end{array}\\\\\\
\Rightarrow \dfrac{1}{20}+\dfrac{1}{x}=\dfrac{1}{14}$$

Assuming that by "legs" you mean thew sides that aren't the hypotenuse, then just use the arctan function.

That is, you have tan(A) = 50/45 so A = atan(50/45)  (i.e. tan^-1(A))

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{50}}}{{\mathtt{45}}}}\right)} = {\mathtt{48.012\: \!787\: \!504\: \!183^{\circ}}}$$

The other angle (B, say) is atan(45/50)

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}^{\!\!\mathtt{-1}}{\left({\frac{{\mathtt{45}}}{{\mathtt{50}}}}\right)} = {\mathtt{41.987\: \!212\: \!495\: \!817^{\circ}}}$$

You should check that these two sum to 90°