All Answers 355923 Answers

So 2330/865 = 0.37 

Multiply by 100 to get it in percent

0.37 x 100 = 37% 

Here's the answer to  the second one, LF :  https://web2.0calc.com/questions/please-help-asap_22

First one

P(A)  = 5/8       P(B)  =  3/4    P (A  ∩ B)  =  15/32 

D is the true statement because

P(A  ∩ B)  = P(A) P(B)

15/32   =  (5/8) (3/4)

15/32  = 15/32

Last  one

Prob of a boy chosen at random does not wear glasses  =  33/45  = 11/15  = 73%

Yes, I did. 

Oh yes, I did get them wrong...

A city employee collected survey data from 2,330 randomly selected residents. A total of 865 of these residents said that they thought the city should devote more city funds to repair roads. To the nearest percent, what is a good estimate of the percentage of all residents who thought this?

Thats how its supposed to be....

Do you have the question pasted in correctly?

865/230 = 3.7 not 376. 

You're probably adding extra zeroes, try it again! :) 

Thats what I thought... 

These are the answer choices 

37

38

73

50

Well   865/230 = 376 %      SO I think you may have your numbers incorrect?

Maybe    230 out of 836?  = 27.5 %

Looks like you got it.....it is tangent at pi/3 , -0.68

y  = x - tan x

y' = 1 - sec^2x

At  pi/3   the slope is  1 - sec^2 (pi/3)   =  1  - (2)^2  =   1 - 4  = -3

And...at pi/3, y  =   pi/3  - tan (pi/3)    =  pi/3  - √3

So....the equation  of the tangent line at    (pi/3, pi/3 - √3 )  is

y  = -3 (x - pi/3) + pi/3 - √3      simplify

y = -3x + pi + pi/3  - √3

y = -3x + (4/3)pi - √3

Here's the graph, Julius :   https://www.desmos.com/calculator/aheivaxqtb

865/230 = 3.7% 

You are correct....!!!!

 35°  is a first quadrant angle....and all the trig functions are positive in the first quadrant

But  145°  is a second quadrant angle....and the cosine is negative in this quadrant

Tysm <3

              Red      White

Jar 1       72        108

Jar 2     117          63

Explanation....

Jar 1 contains 40%  red  marbles of 180   = .40 * 180  =  72

So...Jar 1  also contains 180 - 72  = 108 white marbles

Jar 2 contains  35% white  = .35 * 180  =  63

And it must also contain 180 - 63  = 117 red

I thought the last one was either 0.73 or 0.41 (let's just wait for the math genius lol)

Oh yes that's exactly what I did

Haha that's alright 

omg , yeah, lol that's embarrassing. 

Normally I put the picture in and jsut explain it really good, lol I explain how the solutions mean where they cross and circle the points where they do. 

Also it's D right

Lol ty, I knew I had to graph it but I wasn't sure if I should explain how to get it with a little more info

Girl, I got you! Hang on one second! 

It's B, and here is why! 

Hi Melody,

so sorry for replying only now...when working with quadratic patterns and/or combinations of arithmetic and geometric sequences, we have a few formulas we can use:

what others call polynomial of degree 2, we refer to as either quadratic or "a second differences sequence". The same thing I know..

The 1st formula is

\(Tn=an^2+bn+c\)

Then

\(2a=d2\), so 2a is equal to the second difference.

then

\(3a+b=T_2-T_1\)

and lastly

\(a+b+c=T_1\)

I got D for the second one :/

Thank you very mutch :D

How to get from this:

sk^1/3 = δk.

to this

k^2/3 = s/δ

k = (s/δ)^3/2.

\(\begin{array}{|rcll|} \hline \delta k \quad &=& sk^{\frac{1}{3}} \quad & | \quad : \delta \\\\ k &=& \dfrac{s}{\delta} k^{\frac{1}{3}} \quad & | \quad k = k^1 \\\\ k^1 &=& \dfrac{s}{\delta} k^{\frac{1}{3}} \quad & | \quad k^1=k^{\frac{3}{3}} \\\\ k^{\frac{3}{3}} &=& \dfrac{s}{\delta} k^{\frac{1}{3}} \quad & | \quad : k^{\frac{1}{3}} \\\\ \dfrac{ k^{\frac{3}{3}} } { k^{\frac{1}{3}} } &=& \dfrac{s}{\delta} \\\\ k^{\frac{3}{3}} k^{-\frac{1}{3}} &=& \dfrac{s}{\delta} \\\\ k^{\frac{3}{3}-\frac{1}{3}} &=& \dfrac{s}{\delta} \\\\ k^{\frac{3-1}{3}} &=& \dfrac{s}{\delta} \\\\ k^{\frac{2}{3}} &=& \dfrac{s}{\delta} \\\\ \left(k^{\frac{2}{3}}\right)^{\frac{3}{2}} &=& \left(\dfrac{s}{\delta} \right)^{\frac{3}{2}} \\\\ k^{\frac{2}{3}\cdot \frac{3}{2}} &=& \left(\dfrac{s}{\delta} \right)^{\frac{3}{2}} \\\\ k^{1} &=& \left(\dfrac{s}{\delta} \right)^{\frac{3}{2}} \\\\ k &=& \left(\dfrac{s}{\delta} \right)^{\frac{3}{2}} \\ \hline \end{array}\)