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You know thats really a hard question which can confuse u the most!lol!

But out here we are doing proper Maths so there are no chances of getting confused with the right answer so ur answer is 

1+1=2 ANSWER

1.)  Solve for w:

b=w-z/v       ---Multiply both sides by v

bv = w-z          ---Add z to both sides

bv+z = w           ---Flip it around

w = bv+z

2.) Solve for w: 

b=rw+r             ---Divide both sides by r

b/r=w+r              ---Subtract r from both sides

b/r-r = w              ---Flip it around

w = b/r-r

Hopefully this makes sence. Basically your just manipulating the problem a little bit to get w = something rather than     b = something.

yes alan good and nice thinking!you might have thought hard for this isnt it!looks like!

I think you might be right Alan.  Good thinking!

Rose has interpreted this correctly exactly as it is written:

8.2*105*(7.7*10 - 1) or 861*(77 - 1) or 861*76 or 65436.

However, it's just possible it was meant to be 8.2*10⁵*7.7*10^-1, in which case it is 63.14*10⁴ or 6.314*10⁵.

Mind you, I've no strong reason for thinking this other than that the -1 in the second set of brackets looks like it wants to be an exponent!!

A square is a special type of rhombus.  And the diagonals of all rhombuses bisect one another at right angles.

So the diagonals divide the rhombus into 4 congruent right angled triangles.

the short sides are  each $${\frac{{\mathtt{7}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{2}}}}}{{\mathtt{2}}}}$$  inches long.  And the side of the rhombus is the hypotenuse

$$\\h^2=\left(\frac{7\sqrt2}{2}\right)^2+\left(\frac{7\sqrt2}{2}\right)^2\\\\
h^2=2\times \left(\frac{7\sqrt2}{2}\right)^2\\\\
h^2=2\times \frac{49\times 2}{4}\\\\
h^2=49\\\\
h=7\;inches$$

OOOHHH! i got the wrong thing!i saw the question wrong!i was subtracting 4 instead of 1 ! i got my mistake!Thanks for the help CPhill!thumbs up from me!

I'll bet I know what you might be doing wrong, rosala

It's in the second set of parenthesis.....

Remember that we're multiplyig the 7.7 x 10 before subtracting the "1"

Try it now......

Rose can you just show me how u got this , i mean the steps!becoz i dont know why im not getting the right answer !

The diagonal of a square is √2 times as long as the length of a side.

So, dividing the diagonal length by √2, we have that the side is just 7 inches.

8x+y=-16

-3x+y=-5          Multiply the second equation by -1 and add it to the first equation

This gives

11x = =11        Divide both sides by 11

x = -1              

Now...just substitute this into either equation to find y......I'll use the first one

8(-1) + y = -16

-8 + y = -16       Add -8 to both sides

y = -8

Check both answers in the second equation

-3(-1) - 8 = -5

3 - 8 = -5

Yep...that works....!!!!

8x + y = -16    ...(1)

-3x + y = -5    ...(2)

Subtract 8x from both sides of (1) to get

y = -16 - 8x    ...(3)

Now eliminate y from (2) by replacing it with the right-hand side of (3)

-3x -16 -8x = -5

Collect the x terms

-11x -16 = -5

Add 16 to both sides

-11x = 11

Divide both sides by -11

x = -1 

Now eliminate x from (3) to find y

y = -16 -8*(-1)

y = -8

Check by putting the values for x and y back into (1)

8*(-1) + (-8) = -16  ok

and (2)

-3*(-1) + (-8) = -5  ok

Thank you both so much! That was really confusing me :P

Factor the "y" out on the left side

y(k + q) = t      Divide both sides by (k + q)

y = t / (k + q)

32 is divisable by 2 so √16*√2.  

It is not the 2 that is important here.  It is the 16

32=16*2

If you want to simplify a surd you have to look for a squared number that goes into it.

squared numbers are (don't worry about 1, it is not helpful)

$$\\1^1=1, \;2^2=4,\;3^2=9,\;4^2=16\;etc\\\\
1,4,9,16,25,26,49,etc$$

$$\begin{array}{rlll}
\sqrt{32}&=&\sqrt{16\times2}\\\\
&=&\sqrt{16}\times \sqrt2&\\\\
&=&4\sqrt2&\\\\
\end{array}$$

so it is pulling out the square number that is the important bit!

Remember that we can write 32 as 16*2

So.......

√32 = √(16*2) = √16 * √2  = 4√2

Thank you!  You are so amazing :D

3√2 - √2 = 2√2

We can set this up as a proportion.

Let the longest side of the smaller triangle = x

Let the longest side of the larger triangle = x + 3

And they're in a 5:4 ratio

So we have

(x+3)/x = 5/4    Cross-multiply

4(x+3) = 5x

4x + 12 = 5x    Subtract 4x from both sides.

12 = x      And this is the longest side of the smaller triangle.

x + 3 = 15    And this is the longest side of the larger triangle.

The answer is 65436 :)

That was the talk of yesterday!now ive come for his help!

No yesterday he had none.GL kept beating him to it lol

He's got no reason to feel bad Zegroes!he has many more posts which he can answer and feel happy again!

and if u feel sad CPhill then i'm with u for ur help!lol!