For, problem 2, I suppose you are including the numbers in between.
I suggest you using a strategy called "complementary counting," subtracting the unwanted from the total.
We can first check the multiples of nine are between 1 and 1000, which is from 9 all the way up till 999, and that is 111 integers.
There are a total of 1000 numbers, and the answer should be \(1000-111=\boxed{889}\) integers.