Melody

@@ What is Happening?  [Wrap4]   Thurs 10/12/15   Sydney, Australia Time 12:43 pm (Really Friday)  ♪ ♫

Hi all,

Todays answer credits are awarded to Heureka, ZavierZz, CPhill, Alan, InjustaGod, Hayley1, Will85237, MathForLife, EinsteinJr and Anima.   Thank you.      

Technical Issues:

How can you post a picture when the picture upload on the forum is not working properly ?

Thanks very much Alan for these instructions.

I used them for the first time today, alan's instructions work well so give it a go :)

x^2=7

\(x^2=7\\~\\ x=\pm\sqrt7\)

y= (7x)-4/(sqrt3(-2) = 7*x-((4/sqrt3(-2)))

I did that the super long way ..

\(y= 7x-\frac{4}{\sqrt[3]{-2}}\\~\\ y= 7x+\frac{4}{\sqrt[3]{2}}\\~\\ y= 7x+\frac{4}{2^{1/3}}\times \frac{2^{2/3}}{2^{2/3}}\\~\\ y= 7x+ \frac{4\times 2^{2/3}}{2}\\~\\ y= 7x+ \frac{2\times 2^{2/3}}{1}\\~\\ y= 7x+ \sqrt[3]{32}\\~\\ \)

y= (7x)-4/(sqrt3(-2) = 7*x-((4/sqrt3(-2)))

I assume you want me to rationalize the denominator  ://

\(y= (7x)-\frac{4}{\sqrt[3]{-2}} \\~\\ y= 7x+\frac{4}{\sqrt[3]{2}} \\~\\ y= \frac{7x\sqrt[3]{2}+4}{\sqrt[3]{2}} \\~\\ y= \frac{7x*2^{1/3}+4}{2^{1/3}} \\~\\ y= \frac{2^{2/3}}{2^{2/3}}\times \frac{7x*2^{1/3}+4}{2^{1/3}} \\~\\ y= \frac{7x*2+4*2^{2/3}}{2} \\~\\ y= \frac{7x+2*2^{2/3}}{1} \\~\\ y= 7x+2^{5/3} \\~\\ y= 7x+\sqrt[3]{32} \\~\\ \)

Thanks Chris and Heureka,

This looks like a really interesting question :)

Well

\(If\;\;\;r=4\;\;\;then\\\pi \div r^2 = \pi \div 16\)

Your Eastern Box Turtle is really cute.    

They hang out in North Carolina, USA.   :))

You can just use the minus sign :)

You are posting some really good answers today Hayley :) 

Yes I got the same answers Chris.   

I just would have put a box around the 2 circles and put 20 in the box. Just to make the venn diagram right :)