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Answer: If you look at 6 months, the total cost is $150, (C).

Good job! You're correct, it is (A) because you have an initial fee of $2.15, then the taxi service charges $1.68 for each mile, so $2.15+1.68x, or 1.68x+$2.15! 

13. $(8x^3-6x^4+3)-(3x^3-3+8x^4)= 8x^3-6x^4+3-3x^3+3-8x^4$$=-14x^4+5x^3+3+3=-14x^4+5x^3+6.$

Remember! When you have a negative sign before the parenthesis, the signs change in inside!

13. When you have a negative sign before the parenthesis, the signs change in inside!

So, the answer is -14x^4+5x^3+6, after the calculations!

Use the same method for 14!

Using the key, we find out 4|4=44, which is there! (C). 

It most resembles a bar graph, uses bars and this has pictures! (A) 

This is 4,000 steps and above, so: 12+7+3=22, (D).

Look at the first table, Single.

Column number 6 is in the range, so: 0.25E-3190: 8300-3190=$\boxed{5110}$, or (B).

Hi, RP!

1. Subtracting -3n^2 from -7n^2, we get: $-7n^2-(-3n^2)=-7n^2+3n^2=4n^2.$

2. $(-8x^4y^3)*(2x^5y^2)+7x^9y^5$ , we can remove the parenthesis, then multiply, then add, to attain: $-16x^9y^5+7x^9y^5=-9x^9y^5$.

3. Again: $(-4a^3b^2)^2*(3a^2b)=16a^6b^4*3a^2b=48a^8b^5.$

4. $5c^{-7}d^2*(-cd^2)^4$ , simplify, apply the exponent rule, and finally: $\frac{5d^{10}}{c^3}$ . This might be wrong!!!!

5. $\frac{18w^4x^9}{14w^5x^5}$, division, subtract powers! So, $\frac{18x^4}{14w}$. Reduce it, to $\frac{9x^4}{7w}.$

6. $\frac{15x^2y*-6x^7y}{(3xy)^2}$, remove parenthesis and simplify to get: $-10x^7$ .

Answers:

1. $4n^2$

2. $-9x^9y^5$

3. $48a^8b^5$

4. $\frac{5d^{10}}{c^3}$

5. $\frac{9x^4}{7w}$

6. $-10x^7$

I think you've posted this question multiple times!