tertre

Check: $200, also she made two deposits of $80, so $200+2(80)=200+160=\boxed{360}$ 

$-2+4=2.$

$-1^2=-1*-1=\boxed{1}$.

Negative changes to positive, so $3-(-9)=3+9=\boxed{12}$ .

If Joshua Smith were a single: 0.25(56,500)-3190=14125-3190=10933.

If Joshua Smith were the head of a household: 0.25E-4305=, 0.25(56,500)-4305, 14125-4305=9820.

So, the difference is 10933-9820=1113.

The formula for finding the slope: $\frac{y_2-y_1}{x_2-x_1}=\frac{8-4}{0-2}=\frac{4}{-2}=\boxed{-2}$.

Notice: In the cancellation of a common factor a, we canceled 2a and 3a^3, yielding us with: 2 and 3a^2.

Wait, I can try 20!

20. $\frac{16a^4-40a^2+24a}{12a^3}$, we can factor out a common term 8a from the numerator, so we get: $8a\left(2a^3-5a+3\right)$.

Now, we are left with $\frac{8a\left(2a^3-5a+3\right)}{12a^3}$ . We can factor a common term 4, and cancel $a$ , a common factor. 

Cancel common factor 4: $\frac{2a\left(2a^3-5a+3\right)}{3a^3}$.

Cancel common factor $a$: $\frac{2\left(2a^3-5a+3\right)}{3a^2}$.

So, $\boxed{\frac{2\left(2a^3-5a+3\right)}{3a^2}}$

is our answer!

18. $4(2-3w)(w^2-2w+10)$, we take a good look at the last two terms, excluding the 4: (2-3w) and (w^2-2w+10)

We can expand or distribute the first two terms(2 and -3w) with the rest of the terms. So, we yield: $2w^2+2\left(-2w\right)+2\cdot \:10+\left(-3w\right)w^2+\left(-3w\right)\left(-2w\right)+\left(-3w\right)\cdot \:10$ . We simplify this, to get: $-3w^3+8w^2-34w+20$.

Now, finally, we multiply this terms by 4: $\:4\left(-3w^3+8w^2-34w+20\right)= \boxed{-12w^3+32w^2-136w+80}$, and that's our answer!

I have to go now, bye!

Oops, didn't see your reply, sorry.

Hint: .( target area of triamgle) / (whole area of triangle) = desired probability