tertre

Check: $200, also she made two deposits of $80, so \(200+2(80)=200+160=\boxed{360}\) 

\(-2+4=2.\)

\(-1^2=-1*-1=\boxed{1}\).

Negative changes to positive, so \(3-(-9)=3+9=\boxed{12}\) .

If Joshua Smith were a single: 0.25(56,500)-3190=14125-3190=10933.

If Joshua Smith were the head of a household: 0.25E-4305=, 0.25(56,500)-4305, 14125-4305=9820.

So, the difference is 10933-9820=1113.

The formula for finding the slope: \(\frac{y_2-y_1}{x_2-x_1}=\frac{8-4}{0-2}=\frac{4}{-2}=\boxed{-2}\).

Notice: In the cancellation of a common factor a, we canceled 2a and 3a^3, yielding us with: 2 and 3a^2.

Wait, I can try 20!

20. \(\frac{16a^4-40a^2+24a}{12a^3}\), we can factor out a common term 8a from the numerator, so we get: \(8a\left(2a^3-5a+3\right)\).

Now, we are left with \(\frac{8a\left(2a^3-5a+3\right)}{12a^3}\) . We can factor a common term 4, and cancel \(a\) , a common factor. 

Cancel common factor 4: \(\frac{2a\left(2a^3-5a+3\right)}{3a^3}\).

Cancel common factor \(a\): \(\frac{2\left(2a^3-5a+3\right)}{3a^2}\).

So, \(\boxed{\frac{2\left(2a^3-5a+3\right)}{3a^2}} \)

is our answer!

18. \(4(2-3w)(w^2-2w+10)\), we take a good look at the last two terms, excluding the 4: (2-3w) and (w^2-2w+10)

We can expand or distribute the first two terms(2 and -3w) with the rest of the terms. So, we yield: \(2w^2+2\left(-2w\right)+2\cdot \:10+\left(-3w\right)w^2+\left(-3w\right)\left(-2w\right)+\left(-3w\right)\cdot \:10\) . We simplify this, to get: \(-3w^3+8w^2-34w+20\).

Now, finally, we multiply this terms by 4: \(\:4\left(-3w^3+8w^2-34w+20\right)= \boxed{-12w^3+32w^2-136w+80}\), and that's our answer!

I have to go now, bye!

Oops, didn't see your reply, sorry.

Hint: .( target area of triamgle) / (whole area of triangle) = desired probability