All Answers 356000 Answers

LOL!!!!....sorry, Cal    !!!!!

Let  the  number  of  tests  that  she took to  get  the  84 average  =  n

So  the  number of  total points she had  was  84n

On the next test  she got a  96  and it raised her average  to   86

So....we  can solve for n thusly

84n  + 96

________  =  86          cross-multiply

   n  +  1

84n + 96  = 86 ( n + 1)    simplify

84n  +  96  =  86n + 86        subtract  84n, 86  from both sides

10  =  2n    divide both sides  by 2

5  = n

And let  x  be  the  mark on the last test ......she  has taken 7 tests and we have that

84(5)  + 96  +  x

_____________  =    85             cross-multiply    

       7

84 (5) + 96 + x  =  85 * 7

420 + 96  + x  =  595

516  +  x    =  595

x =  595  -  516  =   79

Um... latex, please? This is kinda unreadable.... I'd love to help, though!

Here is another answer, even though I'm not one of the "awesome people>"

Since all of these cross out, we're left with

2/(n+1)=1/50.

Therefore, the number has to be 1/100, making n+1 100.

Therefore, n=100,

100+99=199.

Hope this helped!

Nice!!

Check https://www.algebra.com/algebra/homework/Percentage-and-ratio-word-problems/Percentage-and-ratio-word-problems.faq.question.1076070.html

Hope this helped!!!

Chris!! You beat me to it!!!

Note   that  in all the  fractions, the  denominator  of the  previous fraction will "cancel"  the  numerator  of the  next

So   at the end  we  will   have  this left

      2                  1

_______  =        ___      cross-multiply

  n +  1                50

50 (2)  =  1 ( n + 1)

100 =   n + 1       subtract  1  from both sides

99   =  n

n + 1  =  100

So....the  sum   of  n , n + 1  =    199

We  have  that

a₃₂  = a₅  + common difference * [ 32 - 5]

-84  = 9  + common difference * [ 27]        subtract  9 from both sides

-93 = common difference * [27]              divide  both sides  by 27

-93/27 =  common difference   = -31/9   

a₂₃  =  a5  + (-31/9) (23 - 5)

a₂₃  =  9  + (-31/9) (18) 

a₂₃ =  9  - 62

a₂₃ = -53

We have the form

y = Acos (Bx +C)  + D

A =  amplitude =   [ high point  - low point ] / 2  = [ 3 - - 11 ] / 2  =  14 / 2  =    7

D =  the vertical shift =   [  hight point + low pont ] / 2  =  [  3 -11] / 2  = -8 / 2  =  -4

The period =    9pi/4  - pi/4   =   8pi/4  =  2pi

B =   2pi/ period  =  2pi / [2pi]   =  1

C =  the phase shift =  pi/4 units to  the right

So.....the  function is

y = 7cos ( x - pi/4)   - 4

In slope-intercept form, the equation is y=8x-20. 

Since its x intercept is 2.5 and y intercept is -20, in standard for the equation is 8x-y=20.

Check https://web2.0calc.com/questions/helppppp_26

Hope this helped!

Nice, Chris!!!

These  types of problems aren't too bad

Each hour, Chase  does  1/3  of the job and Campbell does  1/4  of the job

Add these fractions

1/3  +  1/4  =    7/12

Take the reciprocal  =   12 / 7 hrs  =  time for both working together to do the  job

$25 * 9 months= 225

225 + $30= 255

$255 = Total Payment

$255 - $299.99 = $25.01

The answer is D

Have a great day! :D

Thanks  Bxtteman,

I hope you see my correct answer below.  :)

Thanks LongName :)

Please just post one question per post.  

Besides other reasons you will cut down on the number of people that may answer if you annoy people. 

Asking multiple questions on one post annoys me.

Yes, I tried that answer and it said that it was incorrect.

log_b(x²·y⁴·z)  =  log_b(x²) + log_b(y⁴) + log_b(z)

                     =  2·log_b(x) + 4·log_b(y) + log_b(z)

12₉ + 15₉ + 16₉  =  11 + 14 + 15  =  40

3)  base b is 7; base b + 1 is 8; base b + 2 is 9

If I understand your LaTex, then:

n mod 60 = 43

So, n =60 + 43 =103, and:

103 mod 6 = 1

Note: Search YouTube for "How to solve modular equations"

i know that b is 9 but I plugged in the values and got 40 for s