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Oh ok.

I'd like to know that too  

6^2 / 1^3

$$\frac{6^2}{1^3}=\frac{6*6}{1*1*1}=\frac{36}{1}=36$$

$$\begin{array}{rll}
-4m - 4 &=& 4m\\
-4m +4m- 4 &=& 4m+4m\\
- 4 &=&8m\\
- 4/8 &=&8m/8\\
- 1/2 &=&m\\
m&=&\frac{-1}{2}
\end{array}$$

An excellent answer Ninja 

You have not used any brackets which means that the lengths are likely to be interpreted wrongly.

these are the lengths given, are they the lengths that were intended? (Probably not)

Please add brackets and were can continue with the question.  Thanks.

Remember: Too many brackets is usually better than not enough!

$$\\2x^2-7xy+\frac{3y}{x^2}-4y^2,\qquad 2x+\frac{4b}{6}x-3y, \qquad x^2-xy-\frac{2y^2}{x^2}-4xy-4y^2$$

For more information look here.

If we subtract 6 from 3, we get -3.

Pretend these are dolars. So we have $3. We then pay someone 6$. How many dolars do you have left?

Well, we pay them the three we have, but then we owe them $3, because they still need $6 total.

We owe them 3 dolars, or we have -3 dolars.

Now let's just put a dot where -3 is on a number line.

Another way to look at this would be we started with 3 (blue dot) and we subtract 6, or move 6 to the left to get our red dot...which is -3

Either way you do it, -3 (which is the red dot) is your answer.

Thanks Alan. 

Anonymous, thanks for joining in, we always like that BUT the idea is to try and help people to learn, NOT just to do it for them. 

75% 

0.75 (as a decimal)

3/4 (as a fraction)

3.04 0.34 .034 4.03 0.304  smallest to biggest.

First sort them into more than 1and 1ess than 1

Hint:  Is $5.60 more than $1?  Is $0.56 more than $1

Maybe just think of them as dollars and cents and order them that way.

$${\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{5}}$$                             

Pretty easy... 

.034   0.304   0.34   3.04   4.03 

;)

I do not know this expansion Alan.  

please post legit questions....

9,843,769,403,527,935,495,500 

We need to know what a,b,c and d are.

What kind of shape is it?

Do you want  the first one or the second one?

(1/2)*m +(1/m)

or

1/(2m) + (1/m)

You might be thinking of the Fields medal.

They are different names for the same thing!

Our troll is very ancient.  He suffers badly from arthritis and sometimes his mind wanders a little. Pay him no heed.  Some creatures just need to be ignored yet tolerated.  

Expand sin(a+x) as a series in x:  

sin(a+x) = sin(a) + x*cos(a) + higher order terms involving multiples of x.

Similarly:

sin(a-x) = sin(x) - x*cos(a) + higher order terms

Therefore, sin(a+x) - sin(a-x) = 2x*cos(a) + higher order terms

(sin(a+x) - sin(a-x))/x = 2cos(a) + higher order terms.

The higher order terms all contain multiples of x, so when x goes to zero, these go to zero and we are left with:

$$\lim_{x \rightarrow 0}\frac{\sin(a+x)-\sin(a-x)}{x}=2\cos(a)$$

Your name may very well appear on the list one day.

If so, it will be listed under the “Idiot Savant” section!

You can ignore our Troll, he lives under our rickety old bridge and is by nature a grouch.  

Your name may very well appear on the list one day.  

However, google may very well harbour the answer that you seek.   

First goto Google and type in Google to see what that site does.

If you figure it out, then type in your question and see what appears.

One thing for sure, your name will never appear on any of the lists