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Since the area of the circle is 50·pi, we can find the radius of the circle:

  A  =  pi·r²     --->     50·pi  =  pi·r²     --->     r²  =  50     --->     r  =  sqrt(50)

The area of the triangle is 15.

This triangle can be subdivided into three triangles OAB, OBC, and OCA.

The area of each of these triangles can be found by using this formula:  A  =  ½·a·b·sin(C)

For each triangle, a = b = sqrt(50), so the area of the three triangles added together is:

  A  =  ½·sqrt(50)·sqrt(50)·sin(alpha) + ½·sqrt(50)·sqrt(50)·sin(beta) + ½·sqrt(50)·sqrt(50)·sin(gamma)

Factoring  A  =  ½·sqrt(50)·sqrt(50)·[ sin(alpha) + sin(beta) + sin(theta) ]

Since this area is 15:

  15  =  ½·sqrt(50)·sqrt(50)·[ sin(alpha) + sin(beta) + sin(theta) ]

  15  =  25·[ sin(alpha) + sin(beta) + sin(theta) ]

  15/25  =  [ sin(alpha) + sin(beta) + sin(theta) ]

  0.600  =  sin(alpha) + sin(beta) + sin(theta)

So im right?

Exactly what the other person said would be my answer I assume you're doing data management I did at the being of the year for me (I'm in grade 7 btw)

So it would be

A) Team D

B) Team A

The most variability means the group with the largest range.

The group with the oldest members on average is the group with the highest mean age.

22 persons shaking hands with 20 persons (each) result in 22 x 20  =  440 handshakes.

However, this is double the actual amount since, when person A is shakomg hands with

person B, B is then (also) shaking hands with person A.

So, we need to divide the answer that we got by 2:  440 / 2  =  220 handshakes.

This is my first time posting. The other one was posted by someone else, so instead of posting the same question, I just reposted it. Sorry anyway. Have a good day!

You have four choices for the bottom strip.

You have three choices for the middle strip (every color but the bottom strip).

You have three choices for the top strip (every color but the middle strip).

4 x 3 x 3  =  36 flags

You just posted this an hour ago, no need to post it again.

If someone can help you then they will. 

Doing this discourages people from helping.

yea! it would be super cool to talk with animals! that one was a hard one to pick!

Melinda will roll two standard six-sided dice and make a two-digit number with the two numbers she rolls. For example, if she rolls a 6 and 3, she can either form 36 or 63. What is the probability that she will be able to make an integer between 10 and 20?  

One of the dice must be a 1, then the other die can be anything.  Either die can be the 1.

This table shows all the possibilities: 

1,1   1,2   1,3   1,4   1,5   1,6  

2,1   2,2   2,3   2,4   2,5   2,6  

3,1   3,2   3,3   3,4   3,5   3,6  

4,1   4,2   4,3   4,4   4,5   4,6  

5,1   5,2   5,3   5,4   5,5   5,6  

6,1   6,2   6,3   6,4   6,5   6,6

You can see that there are 11 rolls that contain at least one 1.  There are 36 rolls possible. 

So the likelihood of getting a total between 10 and 20 is 11/36. 

_.

No, No, No, No, No, No, No, No, No, No.

Sorry.

CPhill's is probably a portrait of him, Melody's kangerroo is from where she lives, alan likes graphing(maybe not)

Heureka uses the standard "h"

EP's isn't a virus it's a joke thing? 

Omi is a genius who is in germany I believe, but isn't a sheep.

Hectitare's is i think a DOG

Asinus is the inverse of sine

maxwong likes cookies

Calculator user uses calculators

Geno has a image of a rhino.

Trust me, I don't know most of the backstories.

I'm sure you don't want to either.

Hint: MaxWong may or may not have been bitten by a radioactive cookie.

Let  Kaye's  age  now  =  K

Then Cristina's age  =  3K -10

In two years we  have  that

3K  - 10  + 2  =  2K      simplify

3K - 8  =  2K        

3K - 2K  =8

K  = 8     .....Kaye is 8 yrs old

Check

Cristina's age  now  = 3(8)  -10  =  14

In two years Cristina =  16

And this is twice Kaye's age now

A) We have  the form

y  = A sin (Bt)

A = the amplitude = 3.2

We can  find B thusly

When  t  =  2,  y  =  3.2

So

3.2  =3.2sin (2B)

1 = sin (2B)

B = pi/4

So  we have

y = 3.2 sin  (pi t / 4)

Here's the graph : https://www.desmos.com/calculator/lndmanq4ij

B)   We want to solve this

1 = 3.2sin (pi t / 4)

(1/3.2)  = sin (pi t/4)

(5/16)  =  sin (pi t  / 4)

arcsin (5/16)  =  pi  t / 4

.3178  =  pi t  /4

.3178 ( 4/pi)  = t ≈  .4046   ≈  .40  seconds

 Given parallelogram ABCD, whose perimeter is 124 units, E is the foot of the perpendicular from A to BC and F is the foot of the perpendicular from A to CD. Also, AE= 7 units and AF= 24 units. The area of the parallelogram ABCD is the sum of area of triangle ABC and triangle ACD

We have,

124=2(a+b)⇒a+b=62units Area of parallelogram=base∗height=7a=24b⇒7(62−b)=24b⇒b=43431=14units⇒a=62−14=48unitsTherefore area of ABCD=7a=7(48)=336sq.units

Hope this helps, whymenotsmart^m^.

 P cannot fall into area ABFE, because then, any triangle DPC is greater than any triangle APB.  P also cannot fall into area EID because all triangles BPC would be greater than all triangles APB.

If P falls into any of the regions IFC, ICG of IGD, all triangles APB will have greater areas than either triangles BPC or CPD. And these areas are 3/8 of the square ABCD = 37.5%.....so that's the probabilty that triangle APB will have a greater area than either BPC or CPD.

Hope this helps, whymenotsmart^m^.

If, in the left-hand column, you subract B from A and not get a remainder, B must be just 1

smaller than A.

Since there is no remainder in the 4's column, there must have been a "borrow" in the 1's

column, resulting in the A of the 4's column becoming reduced to the value of B.

A is one greater than B.

NP, hugo......

yeah, I just accidently told you the answer:(

Wait. 1/1200 is right...

yes!!!

Wait. So I should have done 12 choose 3 times 9 choose 3 time 6 choose 3?

EDIT IT

Yeah CPhill said what I was going to say.

Thanks, Cphill!

oops, I accidently gave the whole answer, sry