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We can't really.

We certainly have not proven that this is a general ratio.

However, the question did not ask us to prove anything and it implied that the answer would always be the same.

So it follows that if we find it for a specific case then we will have the answer that is being asked for.

They must alternate knight, knave, knight, knave, ...etc.  So there are 10 knaves.

This is asking for the eigenvalues of matrix A:

Look very carefully at the terms on the right-hand side of equations (1) and (2) below.  What do you notice?

1)

We can find the area of △BXA this way:

area of △BXA   =   area of △ABC  -  area of △BXC

△ABC  is a  " 30-60-90 "  triangle, and in all  " 30-60-90 "  triangles,

the side opposite the  30°  angle is half the length of the hypotenuse.

BC   =   12 / 2   =   6

Also, the side opposite the  60°  is  √3  times the side opposite the  30°  angle.

AC   =   BC  *  √3

AC   =   6√3

Now we can find the area of  △ABC:

area of  △ABC   =   (1/2)  *  AC  *  BC

area of  △ABC   =   (1/2)  *  6√3  *  6

area of  △ABC   =   18√3

△BXC  is also a  " 30-60-90 "  triangle. So we can say:

BC   =   XC  *  √3

XC   =   BC  /  √3

XC   =    6  / √3

XC   =   2√3

Now we can find the area of  △BXC:

area of  △BXC   =   (1/2)  *  XC  *  BC

area of  △BXC   =   (1/2)  *  2√3  *  6

area of  △BXC   =   6√3

area of △BXA   =   area of △ABC  -  area of △BXC

area of △BXA   =   18√3  -  6√3

area of △BXA   =   12√3

Agree completely....thank you for posting this ♥

Nice!

(1, 2, 4, 5, 8, 10, 16, 20, 25, 32, 40, 50, 64, 80, 100, 125, 160, 200, 250, 320, 400, 500, 625, 800,, 1000, 1250, 1600, 2000, 2500, 3125, 4000, 5000, 6250, 8000, 10000, 12500, 15625, 20000, 25000, 31250, 40000, 50000, 62500, 100000, 125000, 200000, 250000, 500000, 1000000) >>Total = 49 - These are divisors of 1,000,000.

The product of the above 49 divisors =1 x 10^147.

The PRIME factors of 1,000,000 are: 2^6 * 5^6

The product of the PRIME factors is of course=1,000,000.

1 st patient at 1200    in lobby until 12 35

2nd patient at 12 05    in lobby until 12 40

3rd patient   at 12 10   in lobby until 12 45

4th patient   at 12 15    in lobby until 12 50

5th patien   at 12 20      getting a shot at 12 34

6th patient   at 12 25     in lobby until 12 35

7th patient   at 12 30     in lobby until 12 40                                  6 patients are in the lobby at 12 34

Hour hand starts at 5 *30 = 150 ^o    moves 1/2  degree per minute     150 + 1/2 x 51 = 175.5⁰

minute hand moves 6^o per min     6 x 51 = 306^o

306 - 175.5 = 130.5^o

6 patients.

The area of a square ABCE is 1 unit squared.

The area of the region CDE is 1/7 of the full circle with a radius of 1 unit.

The area of the walkway is  7 + pi = 10.14159265 u²   

Can your question be any more vague

2 users have asked this question on here.

Here are the links.

https://web2.0calc.com/questions/help_70293

https://web2.0calc.com/questions/please-help_22469

So I believe the answer is 90.

Yes! Good to realize in this situation we can assume it is a square and then know it is true.

Find the product of all the factors of 1,000,000.

Hello Guest,

the product of all the factors of 1,000,000 is:     \(2^6\cdot 5^6\).

  !

                        (2x + 3y)² - (x + y)²  =  1 + 10xy

(4x² + 12xy + 9y²) - (x² + 2xy + y²)  =  1 + 10xy

       4x² + 12xy + 9y² - x² - 2xy - y²  =  1 + 10xy

                             3x² + 10xy + 8y²  =  1 + 10xy

                                         3x² + 8y²  =  1

This is an ellipse  --  center at (0,0)         x-radius = 1/sqrt(3)          y-radius = 1/sqrt(1/8)

икс,деленное на пять минус икс,деленное на шесть=0,5 часов . От сюда следует,что икс=15миль.

What are the factors of 1000000?

 

The factors of the number 1,000,000 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 32, 40, 50, 64, 80, 100, 125, 160, 200, 250, 320, 400, 500, 625, 800, 1000, 1250, 1600, 2000, 2500, 3125, 4000, 5000, 6250, 8000, 10000, 12500, 15625, 20000, 25000, 31250, 40000, 50000, 62500, 100000, 125000, 200000, 250000, 500000, 1000000.

The area of the walkway is   10.14159265 units squared.   

1. isolate the y : \(5y=-3x+20\)

2. divide both sides by 5: \(y=-\frac{3}{5}x+4\)

ok so the equation is \(y=-\frac{3}{5}x+4\)

the y-int is 4.

the slope is -3/5.

if you combine like terms, \(5y+y-2y=\boxed{4y}\)

Since there are only 32 numbers to try:  0²,  1²,  2², 3², ..., 31²  (32² is larger than 1000), it would be easiest just to try them all.

However, if you want a little more orgainized way, you might consider this:

What is the result when the

--  one's digit is a 1?       1

--  one's digit is a 2?       4                             x

--  one's digit is a 3?       9

--  one's digit is a 4?       6

--  one's digit is a 5?       5

--  one's digit is a 6?       6

--  one's digit is a 7?       9

--  one's digit is an 8?     4                              x

--  one's digit is a 9?       1

So the question becomes:  How many numbers smaller than 32 have a one's digit which is either a "2" or an "8"?

there are 12 on each side,   

how many of those have been double counted?   subtract that number

How many have been triple counted. subtract that number twice,

NOW you do it.  

No one else answer for the guest, thanks.