For what value of r in the formula: f(x) = 2x4 + x3 + x2- 3x + r does f(2) = 0?
Replace x with 2: 2·24 + 23 + 22- 3·2 + r = 32 + 8 + 4 - 6 + r = 38 + r
This value is to equal 0: 38 + r = 0
r = -38
Thank you!!
To find a value that satisfies f( f(x) ) = 2
let's find the inverse of both sides: f(x) = f-1(2).
To find the value of f-1(2), we need to find the x-value of the point that has a y-value of 2.
The point that has a y-value of 2 is (0,2), so the value of f-1(2) is 0.
We now have: f(x) = 0.
Again finding the inverse, we have x = f-1(0)
and the x-value that produces a y-value of 0 is -4 (because the point (-4,0) is on the graph.
This is the only solution.
a=1;p=0;b=a^2+3;printb;c=b;cycle:c=c^2+3;printc;p++;if(p<=18, goto cycle,0) These are the 20 terms of your sequence. Notice that the last and 20th term is 335,690 digits long! The last 10 digits of that number are =1,569,412,499
4 19 364 132499 1 7555985004 3 0821260946 0672880019 9.499501263 E+40 9.024052425 E+81 8.143352216 E+163 6.631418532 E+327 4.397571175 E+655 1.933863224 E+1311 3.739826967 E+2622 1.398630575 E+5245 1.956167484 E+10490 3.826591226 E+20980 1.464280041 E+41961 2.144116039 E+83922 4.597233587 E+167844 2.113455665 E+335689
Note: There appears to be pattern of alternating between 4 for odd numbers and 9 for even numbers.
thank you!
N=2; R=0.04;PV=50000; FV=PV*(1 + R)^N; print"FV =$",FV FV =$ 54,080.00 - Jose's investment after 2 years.
N=2*4; R=0.04/4;PV=50000; FV=PV*(1 + R)^N; print"FV =$",FV FV =$ 54,142.84 - Patricia's investment after 2 years.
$54,142.84 - $54,080 =$62.84 =~$63 - difference between Jose's and Patricia's investments.
Sum(5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100)=1050
Sum(2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40)=420
The difference =1050 - 420 =630
thank you! :))
nevermind i'll post another one. please delete this post
Thank you so much! So x is going to be -3.69 and y is going to be 4.40
Therefore vector a = ⟨ -3.69 , 4.40 ⟩ ?:) Just want to be sure it's right lol
How did you get that radius lmao
a=1; b=1;c=1;p=39;d=(a +2*b+ 4*c) *(4/a + 2/b + 1/c);if(d==36, goto6, goto7);printd, a, b, c;p=p-1;if(p>=1, goto4,0); a++;if(a<50, goto4, 0);a=1;b++;if(b<50, goto4, discard=0; a=1;b=1;c++;if(c<50, goto4, 0)
The minimum value =36 and x, y, z take on an infinite number of values. Here are just a few:
mv x y z
36 4 2 1 36 8 4 2 36 12 6 3 36 16 8 4 36 20 10 5 36 24 12 6 36 28 14 7 36 32 16 8 36 36 18 9 36 40 20 10 36 44 22 11 36 48 24 12
First we need to find the volume of the cube, which is 43, or 64.
The equation for the volume of a pyramid is V=(1/3)Bh, where B is the area of the base and h is the height. So, we need to find B. The equation is B=lw, where l=length and w=width. Since it is a square, they are going to be the same. That means B=8(8), or 64.
What we know:
V=(1/3)Bh
V=64
B=64
Substitute:
64=(1/3)(64)h
Solve:
Divide both side by 64 to get 1=1/3h
Multiply both side by 3 to get 3=h
Your answer is:
h=3
They are serving 3 times the amount of people and will need 3 times the amount of water.
3(1/2)=6
They will need 6 cups of water.
1. e(7)=-72-9(7)
=-49-63
=-112
2. a(-4)=40-(-4)3
=40-(-64) or 40+64
=104
The equation we'll use is an=a1rn-1.
an is the quantity of the nth term, a1 is the first term of the sequence, r is the common ratio, and n is the term you are trying to find.
Given:
a1=-4300
r=-0.1
n=8
an=(-4300)(-0.1)8-1
Calculate:
an=0.00043
Line AB is horizontal. We know that parallelograms have two sets of parallel sides, meaning line CD will also be horizontal, or have a slope of 0.
Next we need to find the slope of line BC, which would be -1/2. That would be parallel to AD.
Point D will be the solution of line CD and AD. The equations for those two lines are:
y=-1/2x+1
y=0
Now substitute.
0=-1/2x+1
-1=-1/2x
2=x
So we take x=2 and y=0 to get the coordinates (2,0).
2+0=2
75th term =-1113 + (19 * 75 - 1)
=-1113 + (19 * 74)
=-1113 + 1406
= 293 - the 75th term
3 m / 45 mph = 1/15 hr = 4 minutes
you must drive that last mile in one minute or 60 mph
x = sqrt 33 * cos 130o = .........
y = sqrt33 * sin 130o= .........
Domain of the equation is the possible values of 'x'
x = 7 8 9 10 is the domain
∑ [4^(n - 4), n, 1, 10] =1/64, 1/16, 1/4, 1, 4.......etc.
If tan is positive then sin and cos are positive (Quadrant I ) or both are negative (quadrant III)
if csc (which equals 1/sin) is negative then cos must be negative also
arctan (1/2) = 26.565 degrees or 206.565 degrees cos = -.8944
The slope of the middle line is 8/11.
The sum of the coeffcients of even degree is (-1 - 2)/2 = -3/2.
