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that is the wrong answer, but it's ok! the answer is actually 0

Ellen can assign jobs in 45 different ways.

64/23

The solutions are c = -2 and c = 3.

The product of the proper integer factors of n is $n^{(x - 2)/3}$

There are C(4,2)*4*3*4*3*44 = 38016 ways of getting two pairs.

thanks!

Parallel lines have the same slope

Perpindicular lines :  If a line has slope  'm'    the perpindicular slope is  - 1/m

      so if   slope   m = 9    perpindicular would be   - 1/9

https://web2.0calc.com/questions/please-help_50731#r2

Parallel lines always have the same slope. In this case, it's -5/4.

Perpendicular lines multiply to -1. In this case, it's 4/5. Note that a simple way to get 4/5 is to reverse -5/4 to -4/5, then multiply by -1 and get rid of the negative sign.

You are very welcome!

:P

BY and CZ are angle bisectors, so by the angle bisector theorem, AZ/AC = BZ/BC and CY/BC = AY/AB. Plugging in some values from the givens gets us $\frac{AZ}{AC} = \frac{8-AZ}{BC}$ and $\frac{4}{BC} = \frac{6}{8}$, so BC = 16/3. Also note that AC = AY+CY = 6+4 = 10, so we have AZ/10 = 8-AZ/(16/3). Solving for AZ gets us 120/23, and since AB is 8, AB-AZ = BZ so BZ = 64/23.

You are very welcome!

:P

Find two convenient points -3,1     and    3,3     compute slope, m  =     (y1-y2) / (x1-x2)

   this is 'm' in your slope intercept form of a line   y = m x + b

     'b' is the y-axis intercept of the line (this occurs when x = 0) ....from the graph this value is '1'

         so your line will be  y = m x +1    (put in your computed value of 'm' )

Draw a line  at  y = 1.8

   it crosses the graph at 3 points....   read down below those points to get the 'x' values to add together

      first one   x = .9

       second one   x = .....

          third one    x = .......

https://web2.0calc.com/questions/help-asappp-in-latex_1

Angles on the same side of a leg are supplemental (add to 180^o)

  sooooo

     5x+15    +    3x + 5   = 180

       8x = 160

          x = 20

aaaannnd:   5y-10   +   3y-10  = 180        y = 25

Thank you so much!!!

|9+2a| < 5

must evaluate     9+ 2a < 5         a<-2

  and                    9+2a > -5         a> -7                    Interval for a :     (-7,-2)

There are four possibilities, illustrated by the following:

The triangles legs are  5 and 12       y (via  pythagorean theorem )  = 13 cm

  origianl area of rectangle was 15 x 20 = 300 cm²

      less the triangle   300 - 1/2 *5*12 = x = 270 cm²

Maximum value of y occus at the vale of x = - b/2a     a = -2   b = 8

    put this value of 'x' in the equation to calculate the max value (y) =.......

240 boxes / ( 30 box/min + 20 box/min) = 240 / 50 min = 4.8 min    =   288 seconds

Let f(x)=x^2-7x+18 and let g(f(x))=2x+3. What is the sum of all possible values of g(8)?

We have f(x) = 8, so x² - 7x + 18 = 8  or  x²​ - 7x + 10 = 0 which factorises as: (x - 2)(x - 5) = 0

Hence x = 2 and x = 5 are two solutions for x

So g(2) = 7  and g(5) = 13  the sum of which is 20.

slope,  m  , between the two points    (y1-y2) / (x1-x2)   =  -2

   perpindicular slope would be  - 1/m   =   1/2

60 x   +   72 (1-x) = 70 (1)

- 12x = -2

x = 1/6  per kilo  of x      5/6 per kilo of y

ratio   x:y   =    1:5