All Answers

#6

+140

0

I am so sorry i didnt read it right omg i am really sorry

CreampuffAug 13, 2020

#5

+33666

+2

You can only cancel x+3 from borh sides (i.e. divide both sides by x+3) as long as x+3 is not zero. Here, x+3 turns out to be zero.

Fortuitously, you still get the right answer in this case! However, performing mathematically illegal operations is not valid, whatever the apparent result.

AlanAug 13, 2020

#2

0

Let the amount of money she came to church with =a

2*a - $20,000 =b - for balance..........(1)

2*b - $20,000 =0...............................(2)

Solve for (1) and ( 2):

a = $15,000 - The amount she came to church with

Check: 2 * $15,000 - $20,000 =$10,000

2 * $10,000 - $20,000 =$0

GuestAug 13, 2020

#2

+33666

+2

I get the following:

AlanAug 13, 2020

#4

+1995

+1

oh okay i didnt see the + which means to the right! thank you for your help

jjennyloveAug 13, 2020

#1

+33666

+2

Use Pythagoras' theorem to find the length of the hypotenuse, then use the definitions of sin, cos and tan

i.e sin = opposite/hypotenuse

cos = adjacent /hypotenuse

tan = opposite/adjacent

AlanAug 13, 2020

#1

+33666

+2

ABC and DBE are similar triangles so DB/AB = EB/CB

(10-x)/(10-x+x) = 3/(3+2) or (10 - x)/10 = 3/5

Hence 10 - x = 30/5

10 - x = 6

x = 4

AlanAug 13, 2020

#2

+33666

+2

Here's another way of doing this for those who don't have a handy facility for factorising large numbers:

AlanAug 13, 2020

#1

0

Since f(x) is divisible by x^3, f(x) is of the form ax^5 + bx^4 + cx^3.

You then want ax^5 + bx^4 + cx^3 + 2 to be divisible by (x + 1)^3. Using long division, you get the equations

-10a + 6b - 3c = 0

4a - 3b + 2c = 0

-a + b - c + 2 = 0

==> a = 6, b = 16, c = 12

So f(x) = 6x^5 + 16x^4 + 12x^3.

GuestAug 13, 2020

#5

+980

+1

Thanks

qwertyzzAug 13, 2020

#4

0

Not sure why you say it is incorrect,

if you solve as instructed: x+1 = - (x+5) you will find x = -3

I think YOU are incorrect... thanx for not really trying though !

GuestAug 13, 2020

#1

0

By Angle Bisector Theorem:

32 / [6x +x] = 24 / [9x - 9], Cross multiply and solve for x

x = 3

GuestAug 13, 2020

#1

0

(g² + 6 )² -27

GuestAug 13, 2020

#3

0

Solve for x:
x^2 + 4 x + 3 = -(x + 3) (x + 5)

Expand out terms of the right hand side:
x^2 + 4 x + 3 = -x^2 - 8 x - 15

Add x^2 + 8 x + 15 to both sides:
2 x^2 + 12 x + 18 = 0

Divide both sides by 2:
x^2 + 6 x + 9 = 0

Write the left hand side as a square:
(x + 3)^2 = 0

Take the square root of both sides:
x + 3 = 0

Subtract 3 from both sides:

x = -3

GuestAug 13, 2020

#2

+1

thank you so much!

GuestAug 13, 2020

#2

+140

0

this is incorrect thanks for trying though

CreampuffAug 13, 2020

#1

0

Factor L side to (x+3)(x+1) then cancel (x+3) from both sides of the equation and solve.... x+1 = - (x+5)

GuestAug 13, 2020

#1

-1

1 - First factor [6^101 + 10^101]

2 - You should get:

2^104 × 2 217557 × 265 896803 424061 × 1568 372427 881573 587879 × 5331 425490 815171 853272 879027

3 - Multiply 2^104 =20,282,409,603,651,670,423,947,251,286,016

4 - Take the square root of the result in 3 above:

5 - You should get: 4,503,599,627,370,496 - This is the largest n. So that:

6 - 4,503,599,627,370,496^2 = Result in 3 above which is a factor of 6^101 + 10^101.

GuestAug 13, 2020

#1

+1

1. The probability is pi/9.

2. When we break off the first piece, the probability that the first piece will be longer than 1 unit is 3/5. (This is because we look at the stick as the interval [0,5], then we can break the stick anywhere between 1 and 4.) We are now left with a stick with a length of 4. When we break off the second piece, the probability that the second piece will be longer than 1 is 2/4 = 1/2. This can happen at either end, so the answer is 2*3/5*1/2 = 3/5.

GuestAug 13, 2020

#2

0

Thank you!!! This helped a lot.

GuestAug 13, 2020

#1