All Answers 356462 Answers

9*9*8*7*6

If we include leading zero the answer is obviously 10*9*8*7*6. 1/10 of these numbers has a leading zero, the other 9/10 do not have leading zero and thus they are five-digit numbers. So, the result is

10*9*8*7*6*(9/10) = 9*9*8*7*6

If I understand your question, then:

1 / 216,                     This is the chance of rolling a total of  3
1 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>total of  4 
1 / 36,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>5 
5 / 108,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>6 
5 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>7
7 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>8 
25 / 216,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>9 
1 / 8,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>10 
1 / 8,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>11 
25 / 216,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>12 
7 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>13 
5 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>14 
5 / 108,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>15 
1 / 36,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>16 
1 / 72,>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>17 
1 / 216>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> 18

So, the value of x =10 and 11 when the 3 dice have the probability of: 27 / 216 = 1 / 8

Write an equation for the graph shown below.

Hello Guest!

\(m = -\frac{1}{3}\\ n=4\\ y=mx+n\)

\(y=-\frac{1}{3}+4\)

  !

If I understand your question, then I assume that she puts 2^k, k  being the 1st, 2nd, 3rd....etc...squares. In other words, she puts: 2^1 grains of rice on the first square, 2^2 on the second square, 2^3 on the third square....and so on. If that is right, then you have the following grains of rice on each square from 1 to 10:

(2, 4, 8, 16, 32, 64, 128, 256, 512, 1024)

The sum of the first 8 squares =2 + 4 + 8 + 16 + 32 + 64 + 128 + 256 =510 grains of rice.

The 10th square has: 2^10 = 1,024 - 510 = 514 grains of rice more that the first 8 squares combined.

By calculus,

\([\mathcal{R}_1] = 30 + \frac{1}{4} \cdot \pi \cdot 10^2 + \int_0^5 \sqrt{100 - x^2} \ dx + \int_0^6 \sqrt{100 - x^2} \ dx.\)

We can write out the areas similarly, to get [R_1] - [R_2] - [R_3] + [R_4] = 92.

The set of all possible values of xyz is 1, -1, 2, and -2

The answer works out to 13/8.

The difference is 104 grains of rice.

Here's a matrix solution:

First, we turn the equation x-y = 7 into an equation in form y = mx+b, so we can find the slope, which is m. We get, y = x - 7, so the slope of the equation x-y = 7, is 1. 

Then we plug in the point (-7, -6) in y = mx + b, getting -6 = -7 + b, because m=1, y = -6, x=-7. Therefore, we can see that b = 1. 

As a result, the equation you are looking for is y = x + 1. 

From Step 0 --> Step 1

It should be equal to 3x - 8x + 2 = 4, not 3x-4x+1 = 4

From Step 0 --> Step 2
It should be eqaul to -x + 1 = 4 not x + 1 = 4. 

This a math/STEM site, not grammar, but I'll try:

1. I think it's resume.

2. I think it's goal.

Grammar is not my strong suit so these may be wrong.

can you explain how you got this?

image blocked:

Parallel lines.....what does that remind me of....parallelogram!

In a parallelogram, the sum of the angles is 360. Therefore, we can say this:

2(71) + 2(51 + y - 6) = 360

142 + 102 + 2y - 12 = 360

232 + 2y = 360

2y = 128

y = 64

Not only do we know the answer, but we also know now that 'x' was a red herring.

:)

Whenever I post on this site, the first posting goes in okay.  But then the second and subsequent posts always goes to an error message.  This ALWAYS happens.  Then lately I started getting a different error message, I think it said 404 error - I don't remember exactly the number - but those stopped a couple of days ago.  But I've always got the error on my second post and still do. 

_.

secant: the reciprocal of a cosine

This just goes to say that the cosine of theta is 1/sqrt(5)

But...how does this help...at all? Well, you could just go and find the sin(arccos(1/sqrt(5)) and waste a lot of time trying, or you could use the fact that:

sin(theta)^2 + cos(theta)^2 = 1
 

With what we know, we can say this:

sin(theta)^2 + (1/sqrt(5))^2 = 1

sin(theta)^2 + 1/5 = 1

sin(theta)^2 = 4/5

sin(theta) = 2/sqrt(5)

Edit: oops, forgot to rationalize the denominator!

Multiply top and bottom by sqrt(5):

2sqrt(5)/5

:)

Opens left or right, vertex: (7, 6); passes through (−11,9) . What is the equation for parabola?

The two sets have 6 elements in common.

5  15  25  35  45  55  65  75  85  95  105  115  125  135  145  155  165  175  185  195  205  215  225  235  245  >>Total = 25

I think its 10

Are you taking AoPS? Lol I am

Uhmm...no it is wrong