All Answers 355864 Answers

Rice weighing 33/4 pounds was divided equally and placed in 4 containers. How many ounces of rice were in each?

(33/4)/4 = 33/16

(4x^2-2x)-(-5x^2-8x)

=4x^2-2x+5x^2+8x

=9x^2=6x is our final answer.

(4x² - 2x) - (-5x² - 8x) = 4x² - 2x + 5x² + 8x = 9x² + 6x

The formula for the area is: (lwh)/3

\(\frac {lwh}3 \implies \frac {8 \cdot 4 \cdot 17} 3 \implies \frac {544}3 \implies 181.\overline {3}\)

\((x – 4)(x + 5) \implies x^2 - 4x + 5x -20 \implies \boxed {x^2 +x - 20}\)

ANSWER: 4/81

Very similar approach:

\(12a + 26b -4b – 16a \implies 12 a - 16 a + 26 b - 4 b \implies -4a+22b\)

Oh!

Do you use apple computers/devices?

You can take a screenshot, go into the photos app, and press the "edit" button.

Then, go to the three dots at the top, and press "markup". From there, you can create text boxes or draw the variables.

But, if you are using windows, I am unsure of how to help... I could just do it for you, but guest already did that. 
 

Maybe you could learn Asympote! It's kind of hard at first, but once you get the hang of it, it would be really easy to add x, y and z to the lines.

(1,3.8)

deleted

First we simplify the equation:

12a+26b-4b-16a

=-4a+22b

Ad thus (c)-4a+22b is our final answer

Do you mind improving the formatting? The layout makes no sense. 

really rare, really rare:)!

This problem is really rare, really rare:)!

Hm, ok. Doesn's seem to be the case in many of the other questions, however, even thoough they are around the same time... 

I considered doing that, but I don't have the editing software for it!

We see that adding 10 to x coordinate and adding -6 to the y coordinate gives us s, so 1/5 of the way is:

Adding 2 to the x coordinate and -6/5 to the y coordinate gives us point:

(1,3.8) this is our final answer.

Not so rare, happens a lot during the period of 1:00 to 2:00 PM GMT

weird....

Aah... one of the rare times that all 3 people who view it answer it. :)

\([ (76+786) *78] 98 \implies 98(78(862)) \implies 98(67236) \implies \boxed {6589128}\)

If the latex didn't render right.

deleted

Answer is 6589128

Thank you! This is what I was looking for.

I'm not sure what you mean by "place the labels". In the Asympote code? Or are you going to draw it? 
 

If you are going to draw it (I recommend you do that, because putting it in the Asympote code looks messy) just put it above the corresponding line.