All Answers 357332 Answers

d+(d+4)==3*(d+2) - 19, solve for d

d = 17 and 17+2 =19 and 17+4= 21

The 3 integers are: 17,  19,  21.

The only "real" solutions is when t = - 5

6^-16 = 36^ - 8

6^-16 = (6^2)^-8

6^-16 = 6^-16

There is also a "complex" solution when t = -5 * [(2.i.pi.n) /ln(6)]

Anyways thanks....I got it

The digit d is 2.

This is incorrect.

The lock combination is 232.

This graph should help:

correct! thanks!

Area of rectangle = 8*4 = 32 

The two quarter circles make a half circle of radius 4, so Shaded area = (1/2)*pi*4^2 = 8pi

Hence non-shaded area = 32 - 8pi 

Use Pythagoras' theorem to get the length of OP

OP = $\sqrt{8^2+15^2}=17$

Hence sin(x) = cos(y) = 8/17

As follows:

i got it, the answer is 32-8pi

The perimeter of triangle PQS is 76.

The area is 64 - 16*pi.

ok but Nerdy kid did get some answers and jugoslav has answered you.

I have not looked at any of these answers but I assume you have, 

Are you not happy with any of them?  

Find the remainder upon a division of $x^4+3x^3-2x^2+5x+1$ by $(x-1)(x-2)(x-3)$.

The coordinates of B(0, 4.2)

a, c and d  are the true statements.

what 2 sum numbers equal 7.5 and product 13.5

Hello Guest!

$xy=13.5\\ x+y=7.5$

$y=7.5-x\\ x(7.5-x)=13.5\\ 7.5x-x^2=13.5$

$x^2-7.5x+13.5=0$

           p            q

$x=- \frac{p}{2}\pm\sqrt{(\frac{p}{2})^2-q}$

$x=3.75\pm\sqrt{3.75^2-13.5}\\ x=3.75\pm0.75$

$x_1=4.5\\ x_2=3$

$y=7.5-x$

$y_1=3\\ y_2=4.5$

$4.5\times 3=13.5\\ 4.5+3=7.5$

  !

It's not hard; it's very simple.

OC = 32        CB = 36  

AC = [ 2(OC + CB)] - CB = 100 

Here's my answer.

z = 180 - 84

5y - 49 + 84 = 180

5y = 145

y = 29

4z = 8     so   z = 2

3x - 2(2) = 11

  so   x = 5

z = 2     x = 5     substitute into first equation t calculate 'y'