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I want it NOW!!!!!!! lol 

ok Thanks

I mailed it to you, it should show up within a week :P

Moderators do that.

Weight on Mercury = [Weight on Earth] / 9.81 m/s^2] x 3.7 m/s^2 =162/9.81 x 3.7 =61.10 pounds.

Before understanding the sphere we have to understand a sphere.

A sphere is a 3-dimensional geometry that is a round shape whose all points on the surface have a fixed distance from a point that is at a definite spot inside it.

This definite point inside the sphere is called the center and this fixed distance is called the radius of the sphere.

A hemisphere is half part of a sphere that is obtained when the sphere is divided into two identical parts by cutting it from the center.

The radius of the hemisphere will be the same as the sphere from which it is obtained.

The base of a hemisphere is a circle so the area of the base is computed as-

Ab=πR2Ab=πR2

The total surface area of the hemisphere-

At=Ab+2πR2At=πR2+2πR2At=3πR2At=Ab+2πR2At=πR2+2πR2At=3πR2

Answer and Explanation:

Given that the area of the base of a hemisphere is 100π.100π.

So

Ab=100ππR2=100πR2=100R=√100R=10 unitsAb=100ππR2=100πR2=100R=100R=10 units

We know that the total surface area of a hemisphere is-

At=3πR2At=3π(10)2At=3π(100)At=300π square unitsAt=3πR2At=3π(10)2At=3π(100)At=300π square units

So the total surface area of the hemisphere is 300π square units.

... Now WHERE IS MY COOKIE!?!?!?!?!?

yes, that's what I got too! nice job!

Check your figures again; the perimeter is not 76.  

                               QP  =  12 

                               QS  =  35  

                               SP   =  37  

The perimeter is the total of the three sides. 

Use Pythagoras' Theorem to find PQ:            PQ²  =  13² – 5²   

Once you've found the value of PQ 

Use Pythagoras' Theorem to find QS:             QS²  =  37² – PQ²    

Now you have all three sides.  Add them up. 

Post back if you don't know how to do square root stuff. 

_.

Wrong theorem dudeguy.  The intersecting chords theorem is the one that applies.  The power point apples to a point outside the circle. 

Thanks but that is not correct

Notice that \(\frac{1}{49}=7^{-2}\)  so we have \((7^{-2})^{4m-2}=7^{-10m-2}\)  or  \(7^{-8m+4}=7^{-10m-2}\)

We can equate exponents:   -8m + 4 = -10m - 2  so  2m = -6  or  m = -3

Base area of a hemisphere = pi x r^2, where r = radius.

pi x r^2 = 100pi           divide both sides by pi

r^2 = 100                      Take the square root of both sides

r = 10 - the radius of the hemisphere

Surface area of a hemisphere WITHOUT THE BASE =2 x pi x r^2

                               =2 x pi x 10^2 + Base area

                               = 200pi + 100pi

                               =300pi

Sorry, I misread the question.

Add them up clockwise from the top:

[5 + 5 + 5 + 9 + 13 + 4 + 3 + 10] =54 cm x 3 yards = 162 yards.

2/(-2/9)=-9

LCM(30, 35) = 210 minutes.

The 2 Buses will be back at the depot 210 minutes after 5pm, or 5pm + 210 minutes =5 + 3.5 hours =8:30pm

Ah never mind, I've got it. 

a=1; c=1^(a+2) + 2^(a+1) + 3^(a-1) + 4^a; if(c==1170, goto3, goto4);printc, a; a++;if(a<1000, goto1, 0)

x = 5

Note: Somebody will give you an algebraic solution.

Perimeter of square = 4x

Circumference of circle =2 x 2 x pi =4pi

4x = 4pi

x = pi

Silver = S

Bronze = 2S

18 - 3  Gold Medals = 15 Bronze and Silver.

S + 2S = 15

3S = 15

S = 15 / 3

S = 5 Silver Medals

5 x 2 = 10 Bronze Medals. 

I figured 1 out on my own so I only need help with 2

(1/49)^(4m - 2) = 7^(- 10m - 2)

(4m-2) Log (1/49) = (- 10m - 2 ) Log 7

(4m - 2)(- 1.6902) = (- 10m - 2)(0.8451)

- 6.7608m + 3.3804 = - 8.451m - 1.6902

- 6.7608m + 8.451m = - 1.6902 - 3.3804

1.6902m = - 5.0706

m = - 11.8314 / 1.6902

m = - 3

Link:https://ph.answers.yahoo.com/question/index?qid=20180123030240AASHvba

P.S. You use IMGflip?

1. The original radius was 12 inches.

2. The total volume of the snow is 26*pi.

Thanks 

6^{3t - 1}  = 36^t-3

6^{3t - 1}  = 6^2(t-3)

3t - 1 = 2t - 6

t = -5