The lucky numbers are the numbers that end with 6. So there are 100 of them that are less than 1000.
All twenty of them shake hands with 18 people. 20 * 18 = a lot of handshakes
10 , 12 , 18 , 20 , 21 , 24 , 27 , 30 , 36 , 40 , 42 , 45 , 48 , 50 , 54 , 60 , 63 , 70 , 72 , 80 , 81 , 84 , 90 , Total = 23 such numbers
20 people have to shake hands with 18 other folks
20 x 18 = 360 but each handshake involves TWO people, so divide by 2 360/2 = 180 handshakes
1, 2, 5, 6, 9 - The largest 5-digit EVEN number =96512. The smallest 5-digit EVEN number =12596.
96512 - 12596 =83916 - The difference between the largest and the smallest EVEN numbers.
(123^33 + 27^54) * (148^327 + 2019^2016) % 10^10 =........0135795076. [These are the last 10 digits]
So, the units digit = 6
A = 1, B = 4, C = 6, D = 8
1468 + 468 +68 + 8 =2012
1 + 4 + 6 + 8 = 19
The smallest number > 3456 =3504
(a) There are 4*4 = 16 ways.
(b) There are six ways.
(c) There are 16 + 14 = 30 ways.
I just looked at it and got 25. All I did was see how much it took to get to the next square after 144 and would that number be evenly divisible by 5. Once you get a number that satisfies the second two conditions, the 37+n is a gimme.
edited to add ~ Zero works too, but I assumed the problem wanted a non-zero solution.
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Juice in constituents = juice in final product
.80 (3) + .20 (1) = x ( 3+1) solve for 'x' the decimal representation of percentage .......
for simultanous equations. I found https://www.equationcalc.com/simultaneous-equation-solver useful
t+s = 41
5t + 8s = 241
x^2 - 4x -32 = 0
(x + 4 )(x - 8 ) = 0
x = -4 or +8
All you need to do is to use the last 2 digits of each number, and the other 98 digits cancel each other, and you will get the same result:
[83 x 85] - [81 x 87] =7,055 - 7,047 = 8 - which is the result.
Rows x columns
2 x 3
Assuming two numbers:
5 x 8 = 40
5 + 8 = 13
Three numbers 5 x 4 x 2 11 (?)
PLEASE HELP ASAP
Second question
x = slower car time x+4 = faster car time
120 (x+4) = 2 (90) x
120x + 480 = 180 x
x = 8 hours 8hours at 90 k/hr = 720 km
10 x 4 20 x 2
Work = F x d F = ma
W = (.018 kg)(9.81 m/s^2) x .05 m =.............. joules
Let the distance covered by the slower car = D Let the time taken by the slower car = T
90T = D......................(1) 120*[T+4] = 2D..........(2)
T = 8 hours - time taken by the slower car. D = 720 km - distance travelled by the slower car.
PLS HELP! I WAITED 4 HOURS!
YZ = 17/2.
There are 792 - 4*6 = 768 for Marvin to reach (5,7).