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Can you explain?

With no restrictions and empty boxes allowed, we have:

[4 + 3 - 1] nCr [3 - 1] = 6 C 2 = 15 ways

there are 45 girls

I do not know the answer but I think there are other ways like

4 0 0

0 4 0 

3 0 1

1 0 3

2 2 0

0 2 2      etc

Looks like three ways to me. 

              1     1     2    

              1     2     1    

              2     1     1    

OK....do not know what you are asking, but they will pay   119% * 52 = 1.19 * 52 = 61.88

  You could estimate by saying 20% of 50 = 10        52 + 10 = $ 62

Calculate h = 20

20 = -16t^2 + 150t + 5      solve for t   using Quadratic Formula

  you will get two values....one is arrow going up....the other (larger) is arrow comong down...

No, because his calculation should be 30% of 520.     Would be my answer......

See previous post ,.......

(Continued.....)

75 students in class    60% are girls

.60 (75) = 45 girls

vertex = -1,0

y = a(x+1)^2  + 0     now put in the point on the graph (0,1)   to calculate a = 1

y = (x+1)^2

The answer is 16.

There are 5 different possible values for the median.

60% are girls.....then 40% are boys and this number is 30

40% * x = 30

x = 75

14/15   /   7/3    =      14/15  *  3/7   =   42/105     simplify as needed

You are given the equation for height of the ball......when the ball hits the ground, h will = zero

0 = -16t^2 + 32t + 7        solve for t  using quadratic formula   (throw out any negative value of t)

Draw yourself a picture of this isosceles triangle.....you need to find the height by dropping a line from the apex to the base to form a right triangle.....then you can calculate height:

h^2 + (1/2b)^2 = 25^2

h ^2 = 25^2 - (1/2 (40))^2

h = 15

Now you can calculate sine ACB = opposite/hypotenuse =   h/25 = 15/25 = 3/5 = .6

tan 70   =   opposite side/adjacent side        in a right triangle

              =  height / 12

tan 70 = height / 12

12 tan 70 = height               Do you see now?  

*** edited***

Find 'h' of the isosceles triangle

(sqrt 70 )^2 =  (1/2sqrt 28)^2 + h^2

h= sqrt 63

Area = 1/2 b h   = 1/2  sqrt 28  sqrt 63         you can finish......

You could also do the Heron's Formula calculations to find area (though it is longer) :

https://www.mathopenref.com/heronsformula.html

   SORRY .... I see your answer method now !   I read the question incorrectly as an isosceles triangle rather than equilateral triangle ....     D'Oh !

Amount of income  at 10% = .10 (x)

Amount of income  at 6%   = .06(2x)           summed = 2640

.1x + .12x = 2640       solve for x   the 10% amount    then 6% amount = 2x

You lost me on this one, asinus.....

    can you explain this step? :

a^2 = (a/2)^2 + h^2         won't that just give you the side length and not the base length?  

                                              Seems to me that we need more info to solve this Q  

a total reaction time of 4.6 seconds

   I will assume this means the brakes get applied after 4.6 seconds

      the car will have travelled   4.6 x 11 m/s    before braking = 50.6 m

then xf = xo + vo t + 1/2 a t^2     and    vf = vo + at

vf = 0 = 11   -8.2 (t)      solve for t = 1.3415 seconds

xf = xo + vo t + 1/2 at^2

    = 0   + 11 (1.3415)  - 1/2 (8.2)(1.3415^2)

  = 7.38 meters

7.38 + 50.6 = 57.98 meters     

Correct!

= 0.461538 461538 4615...   six digits repeat

453/6 digits = 75 R 3