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x  from 2 to 14  is 12     need 24 more     14 + 24 = 38

y from -2 to 4   is   6      need 12 more      4 + 12 = 16

(38,16)

See  VERY similar Q just posted:

https://web2.0calc.com/questions/sides-of-triangle

120  130  131  140  141  142  150  151  152  153  160  161  162  163  164  170  171  172  173  174  175  180  181  182  183  184  185  186  190  191  192  193  194  195  196  197  230  240  241  250  251  252  260  261  262  263  270  271  272  273  274  280  281  282  283  284  285  290  291  292  293  294  295  296  340  350  351  360  361  362  370  371  372  373  380  381  382  383  384  390  391  392  393  394  395  450  460  461  470  471  472  480  481  482  483  490  491  492  493  494  560  570  571  580  581  582  590  591  592  593  670  680  681  690  691  692  780  790  791  890  Total =  120 such numbers

Theoretical max = 200 - 26 =   174 BPM

    Target = 80% * 174 =  .8 * 174 ≈ 139  BPM

Triangle side length rule states the sum of any two sides must be greaater than the remaining side

17 + 12 = 29

   so other side could be as long as  28 ( integer)

10 bux/day  *  3/5  =  30/5 = 6 bux/day

Refer to image below:

180-BMC = CMA                  BAC = CMA          MCB= CBM

180-BMC + A + A = 180                   BMC+A=201    SO    A = 201-BMC

180-BMC     +  2* (201-BMC) = 180

∴  BMC = 134^o

                                          (   THEN   CMA = 180 - 134 = 46            AND      A and  C = 67 )

Since BMC = 134    then the other two angle in the triangle on the left =   (180-134)/2 = 23^o = angle B

(100/5 + 100/25 + 200/5 + 200/25 + 200/125 +300/5 + 300/25 + 300/125)==147 zeros

it did very much ty

Hey there, Choff!

 2000% is equivalent to 20*100%. Therefore,  2000% of a number is the same as 20 times that number.  4 quarters is a dollar, so Bryden will get  20*1= 20 dollars.

Hope this helped!

( ﾟдﾟ)つ Bye

Thank you for the answer, but unfortunately that is wrong.

Note that EC  = DC   =   BC

So  triangle  ECB is isosceles with EC  = BC

So  angle ECB  = angle  CBE

And angle  ECB  = 90  + 60  = 150°

So  angle  CBE   = (  180  - 150)  / 2  =   30   / 2  =   15°

hi Alan,

I understand that thank you very much, my problem is how to deal with the 6pq?

Ok Alan, I understand...the 6pq is derived at when the \((p+3q)^2\) is calculated. so you convert the problem to a trinomial basically, and leave the 4th term on its own as a square, so when the trinomial portion is factored, you just add the 4th term and then end up with two terms again which are complete squares as well...then carry on from there to get the final answer...

Thank you very much Alan, I do appreciate..

hi dani0099,

Thank you, will check those out..

The picture is blocked which suggests to me that the image is copyrighted.

Do you have the right to post this question geo?  Where does it come from?

Where it says cross-sections parallel to the y-axis, can you confirm that this really means cross-sections parallel to the yz plane ?

1755/360 = 4 and a bit

so it is 4 revolutions plus a partial revolution

4*360=1440

1755-1440=315

so

Sin 1755 = sin 315

315 degrees is in the 4th quadrant where sin is always negative.

360-315=45 degrees

sin 315 = -sin 45 degrees 

Draw a right angled, isosceles triangle with the legs being 1 unit in length.  

the angles are 90, 45 and 45 degrees

Use pythagoras's Theorum to find the hypotenuse.

From that you can work out what sin45⁰  is.

Thank you :)

I am not sure what 'up to two decimal places' means

12.09 is the only answer that is actually between 12 and 13.

If it means, rounded off to 2 decimal places, then still 12.09 is the only correct answer.

Somewhat unclear question (e.g. what's the significance of the word 'respectively' here?).  However, one interpretation is as follows where the largest area is between the radius 7 and radius 1 circles:

https://web2.0calc.com/questions/hxlp

https://web2.0calc.com/questions/please-help-cphill-melody-alan-just-want-some-hints

Rewrite \(p^2-9s^2+6pq+9q^2\) as \(p^2+6pq+(3q)^2-9s^2\).   Rewrite the first three terms: \((p+3q)^2-9s^2\)

This is the difference of two squares, so can be written as \((p+3q+3s)(p+3q-3s)\)

65 pi