The distance between the two centers is 10.
The discriminant needs to be greater than 0.
\(\Delta = b^2- 4ac = 225 - 32c > 0\)
\(c < \frac{225}{32}\)
225/32 is equal to 7.03125, so c can be any integer from 1 to 7. The sum is 28.
\(-3(1+4i) + i(-2-i) = (-3-12i) + (-2i +1)= \boxed{-2 - 14i}\)
Here are the sums of the digits of the numbers you listed in order:
1, 8, 2, 5, 6, 10, 6, 12, 6, 7, 8, 7, 20, 13, 7, 11, 12, 9, 12, 15, 16, 13, 13, 16, 17
Count the ones that are odd.
Diameter= 0.4 cm ==> \(V = \frac{4}{3}\pi r^3 = \frac{4}{3} \pi \cdot 2^3 = \frac{32}{3} \pi\), or about 33.51 cm^3.
Each lead ball has a mass of (33.51)(11.3) = 378.663 g.
So, 5000 balls have a mass of 1,893,315 g or 1,893 kg.
The medians intersect at the centroid.
Using telescoping series, the sum becomes 9/2.
This is a geometric sequence with starting term 3/16 and common ratio 4.
The third term is c(3) = c(1) * 4^2 = 3.
You can simply plug this into your calculator.
\(\sec(19^{\circ}) = \boxed{1.057}\)
The answer is D.
1. 196 = 14^2 = 2^2 * 7^2
2. GCD(7a^3, 54a^2) = a^2
3. GCD(108, 162) = 54
Primero: $15.10
Usar dinero: $1.40
Total: 15.10 - 1.40 = $13.70
I am sorry.
\(15x^2 + 31x + 2 = \boxed{(15x+1)(x+2)}\)
Depending on which way you wanted to format the question:
m^4 = 5^4 = 625
4m = 5 * 4 = 20
13 * 12 * 47 = 7332 days
(avg cloudless days in a month x months in a year x years)
There are 180/2pi or roughly 6.28 radians in a complete revolution (360 degrees).
48 radians is equivalent to about 2720 degrees, which is equivalent to 200 degrees. Paul is in the 3rd quadrant.
"4 more than p" ==> p+4
"the quotient of n and 8" ==> n/8
I recommend checking out wolframalpha.com or desmos.com.
nickel (III) sulfate
\(\log_a{b} = c \quad \rightarrow \quad a^c = b\)
\(\frac{\sqrt{12x+15x^2}}{\sqrt{3x}} = \sqrt{\frac{12x+15x^2}{3x}} = \sqrt{\frac{(3x)(4+5x)}{3(x)}} = \boxed{\sqrt{4+5x}}\)
Factor: x^2 + 4x - 12 = (x + 6)(x - 2)
The width is x-2 units.
\(7a^7 \cdot a^7 = \boxed{7a^{14}}\)
C to F: (0°C × 9/5) + 32 = 32°F
F to C: (32°F − 32) × 5/9 = 0°C
Replace the numbers with ones of your choosing.
\(99^2 = (100 - 1)^2 = 100^2 - 2(100) +1 = \boxed{9801}\)
