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$m = \frac{-7-3}{0+5} = -2$

The y-intercept is (0, -7).

$\boxed{y=-2x-7}$

x^2 is always positive and the denominator can't be 0 ===> $\boxed{(0, \infty)}$

The sum of the numbers is 2i:

$b+d+f = 2$

$d + f = \boxed{-1}$

This is an optimization problem.

Let x be the increase in bikes sold. So, we can write the expression $(63+7x)(39-1.5x)$.

Simplify and complete the square to find the maximum revenue and the corresponding value of x.

$(Q)(E)(D) = (11-5i)(11+5i)(2i) = (121 + 25)(2i) = (146)(2i) = \boxed{292i}$

(using difference of squares)

By the way, are you three people in the same class or one person with two alternate accounts?

This is a repost. Hope this helps.

$\sqrt{x^2 - 16} \geq 3$

$x^2 - 16 \geq 9$

$x^2 \geq 25$

$\boxed{x \in (-\infty, -5) \cup (5, \infty)}$

$(4-5i)(-5+5i) = -20-25i+20i - 25i^2 = \boxed{5 - 5i}$

$-10x^2 -11x + 6 \geq 0$

$-(2x+3)(5x-2) \geq 0$

$\boxed{-\frac{3}{2} \leq x \leq \frac{2}{5}}$

$z^2 = (3+4i)^2 = 9 + 12i + 12i + 16i^2 = \boxed{-7 + 24i}$

$\frac{15}{3+2} - 8(3) + 7(5+3) = \frac{15}{5} - 24 + 7(12) = 3 - 24 + 84 = \boxed{63}$

Let the sides be a, b, and c.

$c^2 = a^2 + b^2 - 2ab \cos C.$

You can replace c, a, and b interchangeably. This should help:

-440 + 114 = -326

$25 - x^2 \geq 0 \implies -5 \leq x \leq 5$

$-(x-2) \ge 0 \implies x \le 2$

Put the two inequalities together: $x \in [-5, 2]$. This is an interval of length 7.

$(508+ 1749i) + (-1322 +1949i) = \boxed{-814+3698i}$

2 cos 2x= 1

cos 2x = 1/2

2x = pi/3, 2pi/3

x = pi/6, pi/3

(i / 2)^2 = (i^2) / (2^2) = -1/4

-1/4

In that case, the "2" is called a subscript.

Tenths: GCF(16, 40) = 8

Hundredths: 8 - 3 = 5

Thousandths: 1

Tenthousandths:  9

Decimal: 0.8519

Thousandths: GCF(9, 18, 27) = 9, so it's 3

Hundredths: 3 - 2 = 1

Tenths:  9

Decimal: 0.913

 4 + .8r    = 12 + 0.3r

.5r = 8

r = 16

Let the number of rides you went on be x.

4 + 0.8x= 12 + 0.3x

0.5x = 8

x = 16

You went on 16 rides. 

                              x    +     2

x + 1 |----------------------------

           x^2      +     3x   +   5

         -(x^2      +       x)

          =============

                             2x    +   5

                          -(2x      + 2)

                            =========

                                         3

(x^2+3x+5)/(x+1)  = x+2 + 3/(x+1)