\(m = \frac{-7-3}{0+5} = -2\)
The y-intercept is (0, -7).
\(\boxed{y=-2x-7}\)
x^2 is always positive and the denominator can't be 0 ===> \(\boxed{(0, \infty)}\)
The sum of the numbers is 2i:
\(b+d+f = 2\)
\(d + f = \boxed{-1}\)
This is an optimization problem.
Let x be the increase in bikes sold. So, we can write the expression \((63+7x)(39-1.5x)\).
Simplify and complete the square to find the maximum revenue and the corresponding value of x.
\((Q)(E)(D) = (11-5i)(11+5i)(2i) = (121 + 25)(2i) = (146)(2i) = \boxed{292i}\)
(using difference of squares)
By the way, are you three people in the same class or one person with two alternate accounts?
This is a repost. Hope this helps.
https://web2.0calc.com/questions/domain-and-range_34
\(\sqrt{x^2 - 16} \geq 3\)
\(x^2 - 16 \geq 9\)
\(x^2 \geq 25\)
\(\boxed{x \in (-\infty, -5) \cup (5, \infty)}\)
\((4-5i)(-5+5i) = -20-25i+20i - 25i^2 = \boxed{5 - 5i}\)
\(-10x^2 -11x + 6 \geq 0\)
\(-(2x+3)(5x-2) \geq 0\)
\(\boxed{-\frac{3}{2} \leq x \leq \frac{2}{5}}\)
\(z^2 = (3+4i)^2 = 9 + 12i + 12i + 16i^2 = \boxed{-7 + 24i}\)
\(\frac{15}{3+2} - 8(3) + 7(5+3) = \frac{15}{5} - 24 + 7(12) = 3 - 24 + 84 = \boxed{63}\)
Let the sides be a, b, and c.
\(c^2 = a^2 + b^2 - 2ab \cos C.\)
You can replace c, a, and b interchangeably. This should help:
https://en.wikipedia.org/wiki/Law_of_cosines
-440 + 114 = -326
\(25 - x^2 \geq 0 \implies -5 \leq x \leq 5\)
\(-(x-2) \ge 0 \implies x \le 2\)
Put the two inequalities together: \(x \in [-5, 2]\). This is an interval of length 7.
\((508+ 1749i) + (-1322 +1949i) = \boxed{-814+3698i}\)
2 cos 2x= 1
cos 2x = 1/2
2x = pi/3, 2pi/3
x = pi/6, pi/3
(i / 2)^2 = (i^2) / (2^2) = -1/4
-1/4
In that case, the "2" is called a subscript.
Tenths: GCF(16, 40) = 8
Hundredths: 8 - 3 = 5
Thousandths: 1
Tenthousandths: 9
Decimal: 0.8519
Thousandths: GCF(9, 18, 27) = 9, so it's 3
Hundredths: 3 - 2 = 1
Tenths: 9
Decimal: 0.913
Actually, it's 5040 because the question says product not sum.
4 + .8r = 12 + 0.3r
.5r = 8
r = 16
Let the number of rides you went on be x.
4 + 0.8x= 12 + 0.3x
0.5x = 8
x = 16
You went on 16 rides.
x + 2
x + 1 |----------------------------
x^2 + 3x + 5
-(x^2 + x)
=============
2x + 5
-(2x + 2)
=========
3
(x^2+3x+5)/(x+1) = x+2 + 3/(x+1)
