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You can use the pythagreon theorum. 

a^2 + b^2 = c^2

a^2 + 5^2 = 10^2

a^2 + 25 = 100

a^2 = 75

a = 5sqrt(3) = about 8.7

I hope this helped. :))))

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Scroll down to question asked @ 03 29

awww, I hope you have a good weekend too. :))

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Amplitude = 4      The waveform is   8   From height to low points

period = pi

shifted down from midline = 0 to midline y = -1  

We will need to see the picture of the two rectangular prisms please.

because both sides of the ratio increased by 1 after we added 5 to both sides, that means the ratio is simplified by 5. so, to find out how many are in the bag after you add more, you simply multiply by 5. This means you have 20 red marbles after you added more marbles.

x cannot equal  2    or   0     because you would have a ' 0 ' in the denominator....undefined....not allowed....'verboten'

We can say that 49A+7B+C=121C+11B+A. We can expand into 48A=120C+4B or 12A=30C+B or B=12A-30C. from here, I just guessed and got 502 base 7 and 205 base 11, and 247 base 10.

ok ty

d=123-55=68

c=180-123=57

b=180-68=112

a=180-(68+57)=55

30+GUY+GUY=10 so GUY+GUY=150, and we can dvide both sides by 2, so GUY=75.

6+3+4+sqrt34+3+sqrt10+sqrt34=16+2sqrt34+sqrt10=30.82 I think

Can you show me your work as to how you got 150 ?

30 + GUY + GUY = 180          GUY = ?

a. Because there are two team captains, there are six people possibly chosen, and there are 6 people the first captain can pick, 5 people the second, 4 the first again...etc, so there are 6*5*4*3*2 ways or 6!=720 ways.

b. if francis is picked last, that means that there are 5 people to choose from for the first captain because francis cannot be chosen, then 4 for the second, etc, so we have 5*4*3*2 or 5!=120 ways that francis can be picked last, and we divide that by 720 because that's the total amount of ways, and we get 1/6 or 0.17(rounded)

I am sorry, I meant no disrespect :( I will edit it.

The answer is correct, but do not demean the student for not knowing something.

mili=divide by 1000, so there are 1000 mililiters in a liter.

17+10+22+17+19+sqrt((22-10)^2+19^2)=85+sqrt505

6 numbers for the first digit, 5 for the second digit...etc, so we have 6*5*4*3*2=6!. but, because there are two 2's, two 5's, and two 9's, we have to divide by 2!*2!*2! which is only 2^3, which is 8, so 6*5*4*3*2/8=6*5*3=$\boxed{90}$.

thank you it right

First, (Because I can only use slope intercept form to get to that form) we find slope intercept form, which is y = mx + b where m is the slope and b is the constant, we can do $\frac{{y_1}-{y_2}}{{x_1}-{x_2}},$ which is $\frac{3-6}{4-8}=\frac{-3}{-4}=\frac34$. so, now we have y = 3/4 x + b, and we can find out be by plugging in (4,3) for x and y:$3=3+b$, so $b=0$. now, we can multiply both sides by 4, so we get 4y = 3x(we removed the b because b=0), then we can move 3x to the other side, and we get -3x+4y=0.

If you look at the 4 small triangles, two that are shaded and two that are not, you will notice that they have the same base and height, which means they have the same area. We can then swap the shaded witht he unshaded, so the two center triangles are shaded, and the two outer right triangles are not, and because the two iscosolese triangles sum up to 2/3(I'm asuming that the bases of the square are split into 1/3 and 2/3) and they are both shaded, the answer is $\boxed{\frac23}$

Would it be 150 then?

because CD=AD, triangle CAD is iscoscolese, so angle CAD is 50 as well, which makes CDA 80, and because D is on CB, angle ADB+ADC=180, so ADB=80, and because AD=BD, ADB is an iscoscolese triangle, so angle ABC=(180-80)/2=$\boxed{50^\circ}$