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For each question, answer these

a) How much is deposited at the end of each time period   M   or  PMT

b) What is the yearly interest rate expressed as a decimal?

c) How many times a year does it compound?  

d) What is the interest rate per compounding period?      r

e)  What is the total number of time period   n

x = 19.5

The slope is -1 and the y-intercept is (0, 2), so the equation of the line is y = -x + 2.

f(0) + f(1) + f(2)

= (0 + 1) + (1 + 1) + (2^3 + 2(2) + 1)

= 1 + 2 + 13

= 16

Parallel lines are being cut by a transversal.

4x + 12 = 90

4x = 78

x = 19 

4x + 12 = 90 degrees

QR and TS are parallel.

<1 = 76 degrees

<2 = 180 - 119 = 61 degrees

tysm

This is a diagram of two parallel lines being cut by a transversal.

(19x - 4) = 110

19x = 114

x = 6

angles in a straight line ==> (2x + 12) + y = 180

parallel ==> 3x + 23 = y

Solve the system of equations: (x, y) = (29, 110).

\(8439 \div 245 = 34\quad \text{remainder} \quad 109\)

\(QT = \sqrt{53^2 - 28^2} = 45\)

\(RT = \sqrt{117^2 - 45^2} = \boxed{108}\)

\(\sqrt{9^2 - 6^2}= \boxed{6.7}\) feet

I am sorry about that, and thank you for reminding me.

The function p gets bumped up by one at each prime, so the range is [2,4) U [5,6) U [7,8).

Let x = side DE

\(Tan(25) = \frac{9}{x} \)

\(\frac{9}{x} ≈ 0.466 \)

\(x ≈ \frac{9}{0.466}\)

\(x ≈ 19.3\)

There are 6 + 7 + 8 = 21 choices for b and c.

just find how many primes are from 1 to 20. These are 2, 3, 5, 7, 11, 13, 17, and 19, which is 8 primes

halp quickly i need helppppp

Relative to Trisha, Mark is traveling at 4 miles per hour. Trisha has an 8 mile lead, so it will take Mark 2 hours to catch up.

Kyle is definitely wrong, 31/97 cannot be a perfect number, so Kyle must have rounded the number.

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Correct Guest...!

\(1.5z=6\)

\(1.5z\cdot \:10=6\cdot \:10\)

\(15z=60\)

\(\frac{15z}{15}=\frac{60}{15}\)

\(z=4\)

Their difference in spee is 16 - 12 = 4 mph

8 miles will take  8 / 4 = 2 hrs to catch up

Put -1 in the equation

-1 + 6 + 2b- 3c -12 = 0

2b-3c = 7

Put 1 in the equation

1 + 6 - 2b-3c -12 = 0

-2b-3c = 5                                   Now you can solve for a and b   (hint: add the two red equations)

See if you can find   'a'     Hint     (x-a-1)   divided into the equation should leave no remainder....

X-axis intercept occurs when y = 0

3x - 5(0) = 7

3x = 7

x = 7/3

two 5 x 3 faces

plus a 6 x 3 face

   plus 12 x 3 face

     plus   top and bottom   each:  (12+6)/2  * 4          add all of that to get total   in²