All Answers 356733 Answers

It's already in standard form? a = 2, b = 7, c = 3

2 x^2  + 7x   + 3        = 0               a =2    b = 7     c   = 3  

QC =  12 - p     (b)

QA = 2              (h)               area = 1/2 b* h =   1/2  (12-p) * 2 = 12-p

Right triangle    Pythag theorem

hypotenuse = 10

leg = 5       other leg = H

10 ^2 = 5^2 + H^2

75 = H^2                                H = sqrt (75) =  5 sqrt 3

we can use a unit circle, where the x coordinate is cos. we can draw the obtuse triangle, and from the highest point draw a perpendicular line to the x axis, so we have a right triangle, and we notice that the right triangle is a 30-60-90 triangle. because the hypotenuse is 1, we know that the height is 1/2, so the base, or the line that lies on the x coordinate, is $\frac{sqrt3}2$, but because the x coordinate is negative, it must be $\boxed{\frac{sqrt3}2}$

cos (150) =   - cos  30 =  - sqrt 3/ 2

A good way to solve for z is to represent it as a+bi. 

1-iz = -1+iz

2 = 2iz

1 = iz. 

1 = i(a+bi)

1 = ai-b

So a must be 0, and b must be -1. 

z = a + bi

z = 0 + -1i

z = -i

I hope this helped. :))

=^._.^=

74/65 = 1.13846153846

So the change is 13.8%

I hope this helped. :))

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(x+10) + (x+20) = 180 since it's a linear pair. 

(y) + (y-40) = 180 since they're alternate exterior interior angles. 

Try solving for yourself. :)))

I believe you can do it, good luck.

=^._.^=

JUst plug in the values given for   i   R  and  n to calculate  FV

The answer is C.

A = rs

semiperimeter = s = (15 + 41 + 52)/2 = 54

area = A = \(\sqrt{s(s-a)(s-b)(s-c)} = \sqrt{(54)(2)(39)(13)} = 234\)

radius = r = \(\frac{A}{s} = \frac{234}{54} = \frac{13}{3}\)

(2x + 24) + x = 180

3x + 24 = 180

x = 52

2x + 24 = 128 degrees

FV = pv e^rt

78000 = pv e^(.056)(9)

pv = $ 47120.53

sqrt(1 + 4a^2) = 1

1 + 4a^2 = 1

a^2 = 0

a = 0

Thank you so much!

The measure of an exterior angle is equal to half the difference of the measure of intercepted arcs

=   1/2  ( 87-33) = ......... ^o

Guess.

=   x^5-1   y^{3-6  =}  x⁴ y^-3 =    x⁴ / y³

SUrface are of a cylinder  ( not counting the ends)  pi * d    * h        and    h = 2.5 r

area = 112 pi  cm^2

112 pi =  pi   d    2.5 r         remember  d = 2r

112 pi = pi  2 r    2.5 r        divide both sides by pi

112 = 4.5 r                         now solve for 'r'

SInce they put money in tha account at the beginning of the month....starting with month #2   , this is an 'Annuity due' calculation rather than an 'ordinary annuity'.....

FV =  A [  ((1+i)ⁿ -1 )  / i  ] * (1 + i)

A =  $ 100  

    i = interest per period in decimal form    .068/12              (there are 12 periods per year...monthly)

      n = number of periods = 18 * 12  - 1                             (-1 because they did not deposit the first month)

                                         = 215

A = 100 (1+.068/12)²¹⁵  / (.068/12)        *    (1 + .068/12)    =  $ 59806.49

The interest will be this amount minus the amount they deposited    which was   215 * 100

BUG   and   GUY   form a straight line....so they sum to 180 ^o

   and   BUG is   30 + GUY

sooooo     

          30 + GUY       + GUY        = 180^o             Then just solve for GUY ......     

Unit cost calculations....find out which has the lowes cost per lb

A    $  4.98 / 2 lb  =  $ 2.49 / lb

Do the same for B  C and D  to see which has the smallest $ / lb

\(sin(120) = \frac{\sqrt{3}}{2}\)

What is 5 2 1 %  meant to mean.

Is the money deposited at the beginning or end of each 6 months..?

If it is deposited at the end then it is an ordinary annuity and here is the formula