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Correct me if I am wrong, but I am pretty sure that g(x) must have a minimum degree of 9.

\(3f(x) = 3a_8x^8+3a_7x^7+...+3a_1x+3a_0\\ 4g(x) = \quad ?\\ h(x) = b_9x^9+b_8x^8+b_7x^7+...+b_1x+b_0\)

If we are adding the polynomials together, then the only way to get a variable to the power of 9 is if g(x) is of degree 9, at a minimum. Note that multiplication does not affect the degree of the polynomial in any way, so we might as well ignore it for the most part. 

See answer here:  https://web2.0calc.com/questions/problem_32

if you're asking for the whole pie if the pie is 3.14 units then the whole pie is 12.56.

6x-20 = 52

6x = 72

x = 12

y = k x z

60 = k * 3 * 4

k = 5

y = 5* x * z

   = 5 * 6 * 8 = 240

To be honest, I do not recall the correct way to do this problem. Of course, that assumes that there is a "correct" way, but I will just show you my method, and I hope that it makes sense to you! I also created a diagram. Admittedly, this was probably not necessary, but I did it anyway.

OC = OA = OB because those lengths represent radii of the circle O, and the radius of a circle is constant.

Therefore, \(\triangle OCA\) is isosceles, and so is \(\triangle OBA\). Because they are isosceles triangles, the angles opposite those congruent sides have the same measure.

Therefore, \(m\angle OCA = m\angle OCB = 18^\circ\)

By angle addition, \(m\angle ACB = 36^\circ\).

Now, figure \(ACBO\) is a quadrilateral, so that means that the sum of the interior angles is 360. We already know 3 of the angles, so let's find the 4th and final angle.

\(\text{4th interior angle } = 360 - (18 + 18 + 36)\\ \text{4th interior angle } = 360 - 72\\ \text{4th interior angle } = 288\)

\(m\angle AOB = 360 - \text{4th interior angle}\\ m\angle AOB = 360 - 288\\ m\angle AOB = 72^\circ\)

I hoped this helped you on your solving adventures!

Big rectangle     10 x 15    plus two triangles    2 x   1/2 X 5 x 4 = ........ cm²

The greatest difference between f(x) and g(x) is shown below:
 

2²⁸ = 268 435 456

arcsin (-.73)  = - 46.886 degrees     = 313.11 degrees   

   there will also be a value in Q III

    and one more (again in Q III)   for   less than 630 degrees             three

Thank you!

18237643500

This is the third out of 3 times this problem has been posted.

This is the second out of 3 times that this problem has been posted.

Let the side length of a cube be "s."

volume = s^3

surface area = 6s^2

sum of lengths of edges = 12s

90 = 4x - (2x - 6)

90 = 4x - 2x + 6

84 = 2x

x = 42

Try to set a clear goal for yourself, for example, read 2 or 3 sections of a chapter every day. If you find it hard to focus, use the Pomodoro method. Set a timer for 20 minutes and dedicate all of your focus to reading the chapter. Take a 5 minute break (stretch, go walk, eat a snack) then come back to it.

Rearrange to get slope-intercept form: y = -3x/2 + 6

The slope is -3/2 and the y-intercept is (0, 6).

polygon with 7 sides ==> heptagon

interior angle: 180 * 5/7 = 128 4/7 degrees

exterior angle: 360/7 = 51 3/7 degrees

In general, you should isolate the square roots to one side of the equation, then square both sides.

\(5 \cdot \frac{2}{3} = \boxed{\frac{10}{3}}\)

In multiplication, the result is only as significant as the least accurate term.

75.6 x 12.33 = 932.148 = 932

sin = opp/ hyp

sin48 = x/20

x = 20 sin 48 = ..........

700 ( 1 - .055)⁶ =  £ 498.53