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x = 35^o   from the diagram

x + y + y = 180

35  + 2y = 180        solve for 'y'

Nevermind, I guess I did do it. The answer is 68 and 112. Lol.

Multiplying this out the long way is tedious, put will give you the correct answer.

You can use the shortcut:  (x + y)⁶  =  x⁶ + 6x⁵y + 15x⁴y² + 20x³y³ + 15x²y⁴ + 6xy⁵ + y⁶

where  x = 3/5  and  y = 4/5·i.           (You can get the coefficients by using either combinations, or Pascal's triangle.)

Finally, find the absolute value of the answer.

Since one root is  2 - i  another root will be  2 + i.

Since one root is  2 + sqrt(3)  another root will be  2 - sqrt(3).

Written as factors:  [ x - (2 - i) ] · [ x - (2 + i) ] · [ x - (2 + sqrt(3)) ] · [ x - (2 - sqrt(3)) ]  =  0

Multiply this out and select the constant term.

However, since this answer can be multiplied by any non-zero constant and still have the same roots, any non-zero constant will work.

6 ft 4 in = 76 inches

Tan 40 = opp/adj

Tan 40^o =  76/ adj                   solve for adj    which is the shadow length

The domain of  sqrt(25 - x²)  is  [-5, 5].

The domain of  sqrt(x + 25)  is  [-25, infinity)

Since the domain of  sqrt(25 - x²)  is completely contained in the domain of  sqrt(x + 25), the domain of the sum

is the intersection of these two domains:  [-5, 5].

The quadrant that the reflect image is in is quadrant IV. This means the y coordinate is negative but the x stays the same. 

Following, when you reflect any point or shape across the axis, the actual place of the point doesn't change (ie. (2, 1) reflected over x axis --> (2, -1)) 

This means the actual numbers in the coordinate stays the same, but the y values are negative.

Which means B and C are immediately eliminated. Finally, point C is (2 , 1), however answer D says that point C' is (1, -2) which doesn't match up since it should be (2, -1). Therefore your answer is A. 

Missing Sloan's speeds.....

Call the length of each side of the square 'x'.

Draw a line segment from the center of the circle to either of the two points where a square intersects the circle.

There is a right triangle formed by this line segment, one side of a square, and the side formed by two sides of the square.

Since the area of the circle is  60·pi in²  and the formula for the area of a circle is  pi·r²:

     pi·r²  =  60·pi in²     --->     r  =  sqrt(60) in      

The right triangle (described above) has sides  x,  2x,  and sqrt(60).

Using the Pythagorean Theorem:  x² + (2x)²  =  [ sqrt(60) ]²     --->     x² + 4x²  =  60

                                                                                                    --->            5x²  =  60

                                                                                                    --->              x²  =  12

                                                                                                    --->                x  =  sqrt(12)  inches

Same problem

https://web2.0calc.com/questions/i-need-help-with-math_4

-53

Calculate the area of the WHOLE big rectangle     12 x 13 m²

                                     minus the three 'cutouts'

                                      3 x 3       +     2   * 3*3.5   m²

It is -2 for anyone who wants the answer

Very similar....see if you can apply the method to this problem....

https://web2.0calc.com/questions/matthew-has-a-jar-of-368-nickels-and-dimes-he-has#r1

Can you tell me why?

2 equations:

(1) n+d=53 

(2) 0.05n+0.1d = 4

(2) * 100 = 5n+10d = 400 

(1) * 10 = 10n + 10d = 530 

(1)-(2)  = 5n=130 n=26

26 Nickels

i would think so.

3) https://web2.0calc.com/questions/help_44437

2) 2x^2-20=-50 

2x^2+30

x=5 

1) Foil and get 2+2sqrt(5) so 2+2=4

https://web2.0calc.com/questions/i-m-stuck_8

4+2=6

difference d=−31/9.
We have that a5=9
This means that  +d(5−1)=9 or  a1+4d=9.
We have that a32=−84.
This means that a1+d(32−1)=−84 or a1+31d=−84.
We have that d=−319.
We obtained the following system:
a1+4d=9
a1+31d=−84
d=−31/9
Solving it, we obtain that a1=205/9, d=-31/9.
Finally,
a23=a1+d(23−1)=205/9+(−31/9)(23−1)=−53.

Solve after this it should be easy.

Step-by-step explanation:

y = A sin (Bx - C) + D

A: amplitude = max - D or  D - min

B: Period = 2π/B  --->  B = 2π/Period

C: Phase Shift = C/B   --->     C = B · Phase Shift

D: center

Given:

D = 80    the field has a height of 160 ft so the center is at y = 80

A = 65    the min is at 5 yds (15 ft). D - min = 80 - 15 = 65

B = 60    the person next to Darla is 10 yds (30 ft) --> Period = 60

              B = 2π/60 = π/30

C = 5π    the field is 300 ft wide so the center is 150 ft

               Phase Shift = 150.   C = B · Phase Shift = π/30 · 150 = 5π

A = (-)      the band ends down (at 15 feet) so A is negative