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Original area    10  x   10 = 100 mm²

  triple the lengths

        30  x 30 = 900 mm²          New area is 9 times original

like this

\(BD^2=144+16-96cos\angle BCD\\ BD^2=160-96cos\angle BCD\\~\\ but\;\;also\;\; BD^2=121+100-220cos \angle BAD\\ BD^2=221-220cos \angle BAD\\ BD^2=221+220cos \angle BCD\qquad \text{opposite angles in cyclic quads are supplementary}\\~\\ so\\ 160-96cos\angle BCD=221+220cos \angle BCD\\ -316cos\angle BCD=61\\ cos\angle BCD=\frac{-61}{316}\\ so\\ BD^2=160-96*\frac{-61}{316}\\ BD^2=\frac{14104}{79}\\ BD=\sqrt{\frac{14104}{79}}\\ \)

Now do the same for AC

etc

LaTex:

BD^2=144+16-96cos\angle BCD\\
BD^2=160-96cos\angle BCD\\~\\
but\;\;also\;\;
BD^2=121+100-220cos \angle BAD\\
BD^2=221-220cos \angle BAD\\
BD^2=221+220cos \angle BCD\qquad \text{opposite angles in cyclic quads are supplementary}\\~\\
so\\
160-96cos\angle BCD=221+220cos \angle BCD\\
-316cos\angle BCD=61\\
cos\angle BCD=\frac{-61}{316}\\
so\\
BD^2=160-96*\frac{-61}{316}\\
BD^2=\frac{14104}{79}\\
BD=\sqrt{\frac{14104}{79}}\\
 

Original    area    2  ( 6*2 + 6*9 + 2*9) = 168 in^2

double h   (from 9 to 18) area    2 ( 6*2 + 6*18 + 2*18) = 313 in^2

double w   ( from 2 to 4 ) area   2 ( 6*4 + 6*9 + 4*9) = 228 in^2

Doubling w will use   (312 - 228) = 84 in² less material

 2 lw +  2  ld   + 2 wd = area

Now triple l   w   and  d

2 * 3l 3w   + 2 * 3l 3d + 2* 3w 3d

9 * 2 lw   + 9 * 2ld +  9* 2wd     = new area      this is NINE tiems greater than original   9:1

It is C. 

the square on the right is 36, and the remaining triangle has a base of 10 and a height of 12, so the area of the triangle is 60. 60+36 is 96, so C is the answer. 

Its a simple $3:4:5$ triangle: Except it is in the form of $6:8:10$. Therefore Sadie and Eric are 8 meters apart from each other. 

1) ACD = 60 degrees

a + b + c = 6 + 2 + 2 = 10.

The ratio is 45/30 = 3/2.

The quadratic is x^2 - 1.

The URL is invalid. Please refrain from creating extra questions advertising another question. 

500-170 is equal to 330, so 330 gallons escaped. 330/15 is equal to 22, so 22 minutes had passed since the plug was pulled. 

1.2 x    is 120% of x

.4 (1.2x) = .48 x  is   40% of 120% of x      48%

I assume that I have to express this as a percentage of x. 

120% of x is 1.2x. 

40% is 2/5, so it is 1.2x * 2/5, so it is 2.4x/5, which is 4.8x/10, so it is 0.48x. 

Let us test it out. 

Suppose x = 100. 

120% of 100 is 120.

40% of 120 is 48, which fits with our equation 0.48x. 

So the answer is  0.48x

There are 4*3!*3! = 144 ways.

I'm not sure about proving it, but it certainly seems as if the property must hold. How about trying induction?

Guest, that is incorrect, As you can see, you can see the negative sign, so it is $8.12342 \cdot 10^{-7}$ instead. 

8.12342e-07    = 8.12342 X 10^{-7           edited....forgot the  ' - ' sign}

It is to denote a super small number or a large number. 

In this case, 8.12342e-07 is equal to 0.000000812343

Systems of equations: 

x+y = 7

x+4y = 22

x = 7-y

Therefore, we plug it in, 7-y+4y = 22, which is 7+3y = 22, which is 3y=15, and y= 5.

so there are 5 math questions and 2 science questions. 

Only one: 

https://www.desmos.com/calculator/qr75mvikdo

Its 10.5 dimes, since you make two equations, 2x = y and 0.1x+0.25y = 6.30. 

IF you solve it using systems of equations you get 10.5 dimes.\

Very unrealistic, but there are 10.5 dimes. 

The value of a is -4.