All Answers 355982 Answers

x = sqrt(25² - 24²) = 7

Perimeter = 25 + 13 + 24 + 20

P = 82 units

Hi,

Could you please explain how you arrived at the answer? I would like to understand how to solve these problems.

Thanks

Q(a, 0) 

Q(-1, 0)

Hello, the answer if you're looking for it in radical form is 26√330 (26sqrt330) or in decimal form is 472.3134552

The circumcenter is (-2,1).

oh! and forgot to mention: For that tool link, there's a number conversion table, so you can compare all bases up to base 36. 

http://www.unitconversion.org/unit_converter/numbers-ex.html

I had thought of that but I had a brain freeze.  Thanks.

$3(8x^2-5x+1)=8x^2(3)-5x(3)+1(3)=\boxed{24x^2-15x+3}$

There are 10 possible angles.

$2r(4r-8+3)=2r(4r-5)=4r(2r)-5(2r)=\boxed{8r^2-10r}$

$\frac{1in}{0.51mi}=\frac{x}{2.8mi}$

$0.51x=2.8(1)$

$x=\frac{2.8}{0.51}$

$x=$about$\boxed{5.5}$

It must be rotated $\frac{360}{5}=\boxed{72^{\circ}}$

visit here:

https://web2.0calc.com/questions/at-annville-junior-high-school-nbsp-30-nbsp-of-the-students-in-the-math-club-are-in-the-science-club-and-nbsp-80-of-the-students-in-the

By the Pythagorean Theorem, the bases are 13 and 19.  So the area of the trapezoid is (13 + 19)/*24 = 384.

The probability is 1/10.

If it is perpendicular to $y=x+8$, the slope must be $-1$, so the equation for the line is $y=-x+c$ for some c. Substituting $(4,-10)$, we get $-10=-(4)+c$, so $c=-6$. The equation of the line is $\boxed{y=-x-6}$

Listing out the divisors of 720, we have:

1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 30, 36, 40, 45, 48, 60, 72, 80, 90, 120, 144, 180, 240, 360, and 720.

The divisors of 720 that are a multiple of 4 are:

4, 8, 12, 16, 20, 24, 36, 40, 48, 60, 72, 80, 120, 144, 180, 240, 360, 720

There are 30 divisors of 720, and 18 of them are a multiple of 4, so the probability of picking a divisor of 720 that is a multiple of 4 is $\frac{18}{30}=\boxed{\frac{3}{5}}$

However, this method is very time consuming, and any algebraic solution would be much appreciated.

There is a total of $3+1+4+1+1+5=15$ total students, and getting the total number of days missed is $0*3+1*1+2*4+3*1+4*1+5*5=0+1+8+3+4+25=41$ total days missed. This means the average days missed is $\frac{41}{15}=2$ $\frac{11}{15}$. The mode number of days missed is 5, because the most common number of days missed was 5. What I don't understand is that the mean is LESS than the mode, not GREATER than the mode. So the absolute difference between them would be $|5-2$ $\frac{11}{15}|=2$ $\frac{4}{15}$, or, as a common fraction, $\boxed{\frac{34}{15}}$

The next multiple of 3 after 62 is 63...and 273 is the nearest multiple of 3 that is less than 275... the number of multiplyes is given by:

$\frac{273-63}{3}+1=\frac{210}{3}+1=70+1=\boxed{71}$

*Credit, CPhill's answer to this problem: https://web2.0calc.com/questions/how-many-multiples-of-3-are-between-62-and-215*